/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Example 10.7 calculates the fric... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Example 10.7 calculates the friction force needed for a uniform sphere to roll down an incline without slipping. The incline is at an angle \(\beta\) above the horizontal. And the example discusses that the friction is static. (a) If the maximum friction force is given by \(f=\mu_{\mathrm{s}} n,\) where \(n\) is the normal force that the ramp exerts on the sphere, in terms of \(\beta\) what is the minimum coefficient of static friction needed if the sphere is to roll without slipping? (b) Based on your result in part (a), what does the minimum required \(\mu_{\mathrm{s}}\) become in the limits \(\beta \rightarrow 90^{\circ}\) and \(\beta \rightarrow 0^{\circ} ?\)

Short Answer

Expert verified
The minimum coefficient of static friction needed for a sphere to roll without slipping on an incline is \(\mu_{\mathrm{s}} = tan(\beta)\). At \(\beta \rightarrow 0^{\circ}\), \(\mu_{\mathrm{s}} \rightarrow 0\) and at \(\beta \rightarrow 90^{\circ}\), \(\mu_{\mathrm{s}} \rightarrow \infty\).

Step by step solution

01

Calculate normal force

The normal force (\(n\)) that the ramp exerts on the sphere can be calculated using the formula \( n = mg cos(\beta)\) where \(m\) is the mass of the sphere, \(g\) is acceleration due to gravity and \(\beta\) is the angle of inclination of the plane.
02

Derive the force due to gravity

The force due to gravity acting down the sphere can be calculated as \( mg sin (\beta) \) where \(m\) is the mass of the sphere, \(g\) is acceleration due to gravity and \(\beta\) is the angle of inclination of the plane.
03

Derive the friction force

The friction force (\(f\)) needed for the sphere to roll without slipping down an incline is given by \(f= \mu_{\mathrm{s}} n\). However, since we want the sphere to roll without slipping, \(f\) must also equal the force due to gravity. Therefore, \( \mu_{\mathrm{s}} n = mg sin (\beta) \).
04

Find the minimum static coefficient

To find the minimum coefficient of static friction (\(\mu_{\mathrm{s}}\)), isolate \(\mu_{\mathrm{s}}\) in the equation as follows: \( \mu_{\mathrm{s}} = \frac{mg sin (\beta)}{mg cos (\beta)} \). The mass of the sphere and the gravitational acceleration cancel out, leaving \(\mu_{\mathrm{s}} = tan(\beta)\). This is the minimum value of static friction coefficient needed for the sphere to roll without slipping on an inclined plane.
05

Analyze the limits

After finding the solution for part (a), we can substitute the limiting values of \(\beta = 0^{\circ}\) and \(\beta = 90^{\circ}\) into the equation \(\mu_{\mathrm{s}} = tan (\beta)\). As \(\beta \rightarrow 0^{\circ}\), \(\mu_{\mathrm{s}} \rightarrow 0\) since \(tan(0^{\circ}) = 0\). As \(\beta \rightarrow 90^{\circ}\), \(\mu_{\mathrm{s}}\) tends to infinity, since \(tan(90^{\circ}) = \infty\). This suggests that when the plane is horizontal, no friction is required for the ball to roll without slipping. However, as the angle of the incline increases, more and more friction force is needed until it becomes infinite when the plane is vertical.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Static Friction
Understanding the coefficient of static friction, often represented with the symbol \( \mu_s \), is crucial when studying how objects interact with surfaces. This coefficient is a dimensionless number that represents the ratio between the maximum static frictional force and the normal force exerted on an object.

Put simply, \( \mu_s \) dictates how much grip an object has before it starts sliding on a surface. It varies depending on the materials in contact. In our exercise, we're concerned with finding the minimum \( \mu_s \) that would allow a sphere to roll without slipping down an inclined plane. Remember that this 'minimum' value is the threshold at which the sphere would just begin to slip, so it's what we need to avoid in practical applications for consistent rolling.

To compute the minimum coefficient of static friction on an inclined plane, we equate the frictional force to the component of gravitational force parallel to the plane's surface. The ratio of these two forces gives us \( \mu_s \) as a function of the incline angle \( \beta \), specifically \( \mu_s = \tan(\beta) \).
Inclined Plane
An inclined plane is a flat surface tilted at an angle, \( \beta \), with respect to the horizontal. In physics, inclined planes are studied to understand how forces act on objects resting or moving along the slope.

The importance of an inclined plane in our scenario is twofold. First, it creates a component of gravitational force that pulls the sphere downhill. This component is parallel to the plane and can be described by the equation \( mg \sin(\beta) \). Second, the inclined plane also affects the normal force, perpendicular to the surface, given by \( mg \cos(\beta) \). These two components are essential for analyzing motion on slopes and are directly linked to the frictional forces that impact rolling motion.
Normal Force
The normal force is the perpendicular force exerted by a surface against an object resting on it, acting opposite to gravity. In other words, it's the support force provided by the surface.

When an object is on an inclined plane, the normal force is critical for calculating static friction, since as previously discussed, the maximum static frictional force equals the product of the coefficient of static friction and the normal force (\( f = \mu_s n \)). It's essential to note that the normal force is not always equal to the object's weight, especially on an incline. Instead, on an incline, it's determined by the angle of the plane and the weight component perpendicular to the surface, which can be found with \( n = mg \cos(\beta) \). Not only does normal force help in calculating friction, but it also plays a pivotal role in determining the stability of the object on the plane.
Roll Without Slipping
When a sphere rolls without slipping, every point on its surface remains stationary relative to the contact surface at the point and the exact moment of contact. In essence, the sphere rotates about its contact point without skidding.

For rolling motion without slipping, the frictional force is necessary to avoid slipping and is exactly balanced by the component of the gravitational pull trying to slide the sphere down the incline. This is a dynamic state of equilibrium that allows the sphere to rotate on the spot with angular velocity that correlates with its translational velocity down the slope. The condition for rolling without slipping is often essential to ensure control and predictability in the motion of objects, such as vehicle tires on a road or a bowling ball on a lane.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In your job as a mechanical engineer you are designing a flywheel and clutch- plate system like the one in Example \(10.11 .\) Disk \(A\) is made of a lighter material than disk \(B\), and the moment of inertia of disk \(A\) about the shaft is one-third that of disk \(B .\) The moment of inertia of the shaft is negligible. With the clutch disconnected, \(A\) is brought up to an angular speed \(\omega_{0} ; B\) is initially at rest. The accelerating torque is then removed from \(A,\) and \(A\) is coupled to \(B\). (Ignore bearing friction.) The design specifications allow for a maximum of \(2400 \mathrm{~J}\) of thermal energy to be developed when the connection is made. What can be the maximum value of the original kinetic energy of disk \(A\) so as not to exceed the maximum allowed value of the thermal energy?

The mechanism shown in Fig. \(\mathbf{P} \mathbf{1 0 . 6 4}\) is used to raise a crate of supplies from a ship's hold. The crate has total mass \(50 \mathrm{~kg} .\) A rope is wrapped around a wooden cylinder that turns on a metal axle. The cylinder has radius \(0.25 \mathrm{~m}\) and moment of inertia \(I=2.9 \mathrm{~kg} \cdot \mathrm{m}^{2}\) about the axle. The crate is suspended from the free end of the rope. One end of the axle pivots on frictionless bearings; a crank handle is attached to the other end. When the crank is turned, the end of the handle rotates about the axle in a vertical circle of radius \(0.12 \mathrm{~m},\) the cylinder turns, and the crate is raised. What magnitude of the force \(\vec{F}\) applied tangentially to the rotating crank is required to raise the crate with an acceleration of \(1.40 \mathrm{~m} / \mathrm{s}^{2} ?\) (You can ignore the mass of the rope as well as the moments of inertia of the axle and the crank.)

A machinist is using a wrench to loosen a nut. The wrench is \(25.0 \mathrm{~cm}\) long, and he exerts a \(17.0 \mathrm{~N}\) force at the end of the handle at \(37^{\circ}\) with the handle (Fig. E10.7). (a) What torque does the machinist exert about the center of the nut? (b) What is the maximum torque he could exert with a force of this magnitude, and how should the force be oriented?

A 42.0-cm-diameter wheel, consisting of a rim and six spokes, is constructed from a thin, rigid plastic material having a linear mass density of \(25.0 \mathrm{~g} / \mathrm{cm} .\) This wheel is released from rest at the top of a hill \(58.0 \mathrm{~m}\) high. (a) How fast is it rolling when it reaches the bottom of the hill? (b) How would your answer change if the linear mass density and the diameter of the wheel were each doubled?

A solid uniform sphere and a thin-walled, hollow sphere have the same mass \(M\) and radius \(R .\) If they roll without slipping up a ramp that is inclined at an angle \(\beta\) above the horizontal and if both have the same \(v_{\mathrm{cm}}\) before they start up the incline, calculate the maximum height above their starting point reached by each object. Which object reaches the greater height, or do both of them reach the same height?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.