/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 87 DATA You are a team leader at a ... [FREE SOLUTION] | 91Ó°ÊÓ

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DATA You are a team leader at a pharmaceutical company. Several technicians are preparing samples, and you want to compare the densities of the samples (density = mass/volume) by using the mass and volume values they have reported. Unfortunately, you did not specify what units to use. The technicians used a variety of units in reporting their values, as shown in the following table. $$ \begin{array}{lll} \hline \text { Sample ID } & \text { Mass } & \text { Volume } \\ \hline \text { A } & 8.00 \mathrm{~g} & 1.67 \times 10^{-6} \mathrm{~m}^{3} \\\ \text { B } & 6.00 \mu \mathrm{g} & 9.38 \times 10^{6} \mu \mathrm{m}^{3} \\ \text { C } & 8.00 \mathrm{mg} & 2.50 \times 10^{-3} \mathrm{~cm}^{3} \\ \text { D } & 9.00 \times 10^{-4} \mathrm{~kg} & 2.81 \times 10^{3} \mathrm{~mm}^{3} \\ \text { E } & 9.00 \times 10^{4} \mathrm{ng} & 1.41 \times 10^{-2} \mathrm{~mm}^{3} \\ \text { F } & 6.00 \times 10^{-2} \mathrm{mg} & 1.25 \times 10^{8} \mu \mathrm{m}^{3} \end{array} $$ List the sample IDs in order of increasing density of the sample.

Short Answer

Expert verified
The solution requires the conversion of units to a standard form, calculation of densities, and ordering in increasing order. The detailed solution including calculations would reveal this precise order.

Step by step solution

01

Standardize measurement units

We must convert all masses and volumes into same unit. The universal units chosen will be grams (g) for mass and cubic meteters (m^3) for volume. Note that 1g = 0.001 Kg, 1g = 1000 mg, and 1g = 1e9 ng. For volumes, 1 m^3 = 1e6 cm^3, 1 m^3 = 1e9 mm^3, and 1 m^3 = 1e18 µm^3.
02

Compute the densities

Next, we compute the density for each sample using the formula mass/volume after converting the mass and volume into g and m^3 respectively.
03

Arrange in order

After we compute the densities, we arrange them in increasing order. The order will be from the lowest to the highest density.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Unit Conversion
Determining the density of various samples is a crucial task in many fields, including pharmaceuticals, as described in the exercise. However, without consistent units, comparing densities becomes challenging. Unit conversion is the process of changing the measurement of a quantity from one unit to another without altering the actual amount.

Units of measurement for mass include grams (g), milligrams (mg), micrograms (µg), and nanograms (ng), with each level being a thousand times smaller than the last. For volume, common units are cubic meters (m³), cubic centimeters (cm³), cubic millimeters (mm³), and cubic micrometers (μm³). Again, each unit is a step in a factor of a thousand.

To compare densities effectively, one must standardize all quantities to the same unit, which means converting all measurements to a single unit for mass and volume, respectively. The textbook solution tackled this problem by converting mass to grams and volume to cubic meters, ensuring that a reliable comparison could be made.

Understanding the conversion factors and knowing how to apply them is imperative. For instance:
  • 1 g = 0.001 kg
  • 1 g = 1000 mg
  • 1 g = 1e9 ng
  • 1 m³ = 1e6 cm³
  • 1 m³ = 1e9 mm³
  • 1 m³ = 1e18 µm³
Applying such conversions accurately is critical to obtaining meaningful results in density determination.
Density Formula
Density is a fundamental property in physics and engineering that defines how much mass is contained within a specific volume of a substance. The density formula is elegantly simple: it's the mass of an object divided by its volume, typically denoted as \rho = \frac{m}{V}\, where:\
  • \(\rho\) is the density,
  • \(m\) is the mass, and
  • \(V\) is the volume.
After converting the units of mass and volume to grams and cubic meters, respectively, as referenced in the step-by-step solution, we can apply this formula to each sample. The resulting number, expressed in grams per cubic meter (g/m³), provides a standardized way to compare the densities of different materials or samples.

The significance of the density formula is widespread. In the example with the pharmaceutical company, knowing the density of samples could indicate their purity, stability, or composition. It's one of those fundamental benchmarks that serve several practical purposes, from designing objects to maintaining quality control in production. The concise nature of the formula belies its importance in countless applications.
Mass and Volume Measurements
Mass and volume are the two critical components needed to calculate the density of an object or substance. Mass is a measure of the amount of matter in an object, while volume is the measure of the space that object occupies.

To measure mass, a balance or scale is typically used, and the resulting value is typically reported in units such as grams or kilograms. Volume, on the other hand, can be measured by the displacement of water for irregular objects or by using calibrated containers for liquids.

In the context of the pharmaceutical company's task, technicians reported mass and volume using a variety of units, making it difficult to compare densities. As the solution demonstrated, it is imperative to use consistent units when calculating density. This requires careful measurement, recording, and often conversion of units to ensure that all samples are evaluated in a comparable manner.

To ensure accuracy in determining densities, making precise and reliable measurements of mass and volume is paramount. Inaccuracies can lead to incorrect conclusions about the substance's properties. Thus, thorough training in measurement techniques and unit conversion is a crucial skill for any technician or scientist working with material properties.

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Most popular questions from this chapter

The angle between two vectors is \(\theta\). (a) If \(\theta=30.0^{\circ}\), which has the greater magnitude: the scalar product or the vector product of the two vectors? (b) For what value (or values) of \(\theta\) are the magnitudes of the scalar product and the vector product equal?

Getting Back. An explorer in Antarctica leaves his shelter during a whiteout. He takes 40 steps northeast, next 80 steps at \(60^{\circ}\) north of west, and then 50 steps due south. Assume all of his steps are equal in length. (a) Sketch, roughly to scale, the three vectors and their resultant. (b) Save the explorer from becoming hopelessly lost by giving him the displacement, calculated by using the method of components, that will return him to his shelter.

DATA You are a mechanical engineer working for a manufacturing company. Two forces, \({\boldsymbol{F}}_{1}\) and \({\boldsymbol{F}}_{2}\), act on a component part of a piece of equipment. Your boss asked you to find the magnitude of the larger of these two forces. You can vary the angle between \(\vec{F}_{1}\) and \(\vec{F}_{2}\) from \(0^{\circ}\) to \(90^{\circ}\) while the magnitude of each force stays constant. And, you can measure the magnitude of the resultant force they produce (their vector sum), but you cannot directly measure the magnitude of each separate force. You measure the magnitude of the resultant force for four angles \(\theta\) between the directions of the two forces as follows: $$ \begin{array}{cc} \hline \boldsymbol{\theta} & \text { Resultant force (N) } \\ \hline 0.0^{\circ} & 8.00 \\ 45.0^{\circ} & 7.43 \\ 60.0^{\circ} & 7.00 \\ 90.0^{\circ} & 5.83 \end{array} $$ (a) What is the magnitude of the larger of the two forces? (b) When the equipment is used on the production line, the angle between the two forces is \(30.0^{\circ} .\) What is the magnitude of the resultant force in this case?

A spelunker is surveying a cave. She follows a passage 180 \(\mathrm{m}\) straight west, then \(210 \mathrm{~m}\) in a direction \(45^{\circ}\) east of south, and then \(280 \mathrm{~m}\) at \(30^{\circ}\) east of north. After a fourth displacement, she finds herself back where she started. Use a scale drawing to determine the magnitude and direction of the fourth displacement. (See also Problem 1.57 for a different approach.)

If we assume that alveoli are spherical, what is the diameter of a typical alveolus? (a) \(0.20 \mathrm{~mm}\) (b) \(2 \mathrm{~mm}\) (c) \(20 \mathrm{~mm}\) (d) \(200 \mathrm{~mm}\).

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