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Vector \(\vec{A}\) has magnitude \(5.00 \mathrm{~m}\) and lies in the \(x y\) -plane in a direction \(53.0^{\circ}\) from the \(+x\) -axis axis measured toward the \(+y\) -axis. Vector \(\vec{B}\) has magnitude \(8.00 \mathrm{~m}\) and a direction you can adjust. (a) You want the vector product \(\vec{A} \times \vec{B}\) to have a positive \(z\) -component of the largest possible magnitude. What direction should you select for vector \(\overrightarrow{\boldsymbol{B}} ?(\mathrm{~b})\) What is the direction of \(\overrightarrow{\boldsymbol{B}}\) for which \(\overrightarrow{\boldsymbol{A}} \times \overrightarrow{\boldsymbol{B}}\) has the most negative \(z\) -component? (c) What are the two directions of \(\overrightarrow{\boldsymbol{B}}\) for which \(\vec{A} \times \vec{B}\) is zero?

Short Answer

Expert verified
The direction of vector \(\vec{B}\) for maximum positive Z-component is \(233.0^{\circ}\) from the +X-axis; for maximum negative Z-component, it is \(53.0^{\circ}\) from the +X-axis; and for the cross product to be zero, the directions are \(53.0^{\circ}\) and \(233.0^{\circ}\) from the +X-axis.

Step by step solution

01

Determine the direction of vector B for maximum positive Z-component

Since a cross product operation between vectors gives a vector perpendicular to the plane of the vectors and the direction is determined by the right-hand rule, vector \(\vec{B}\) should be in the negative Y-direction to yield the maximum positive Z-component. This happens when \(\vec{B}\) is perpendicular to \(\vec{A}\) and the angle from the +X-axis is \(53.0^{\circ} + 180.0^{\circ} = 233.0^{\circ}\).
02

Determine the direction of vector B for maximum negative Z-component

For a maximum negative Z-component, \(\vec{B}\) should be in the positive Y-direction (opposite direction from Step 1). This happens when \(\vec{B}\) is perpendicular to \(\vec{A}\) and the angle from the +X-axis is \(53.0^{\circ}\).
03

Determine the directions of vector B for which the cross product is zero

The cross product of two vectors is zero if the vectors are parallel or anti-parallel. This means that \(\vec{B}\) should lie along the same line as \(\vec{A}\) and the directions from the +X-axis should be \(53.0^{\circ}\) and \(53.0^{\circ} + 180.0^{\circ} = 233.0^{\circ}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Product in Physics
In physics, the vector product, also known as the cross product, is a binary operation on two vectors in three-dimensional space. It has significant applications in various fields, ranging from mechanics to electromagnetism. Unlike the dot product, which results in a scalar, the cross product of two vectors results in another vector that is perpendicular to the plane in which the original vectors lie.

The magnitude of the cross product is given by the product of the magnitudes of the two vectors and the sine of the angle between them. Mathematically, if vector \( \vec{A} \) and vector \( \vec{B} \) are the two vectors, and \( \theta \) is the angle between them, the magnitude is expressed as \( \| \vec{A} \times \vec{B} \| = |\vec{A}| |\vec{B}| \sin(\theta) \). This formula highlights the fact that the magnitude of the cross product is maximum when the angle \( \theta \) is 90 degrees, implying the vectors are perpendicular to each other.
Right-Hand Rule
The right-hand rule is a simple mnemonic for understanding orientation conventions for vector operations in three dimensions. Specifically, it helps to determine the direction of the vector resulting from a cross product. To apply this rule, you extend your right hand with the index finger pointing in the direction of the first vector (\( \vec{A} \) in our exercise), and your middle finger extending at right angle in the direction of the second vector (\( \vec{B} \)). Your thumb, which is also at right angles to the index and middle fingers, will point in the direction of the cross product vector \( \vec{A} \times \vec{B} \).

This rule is invaluable in answering problems like our exercise. It allows us to visualize that for the cross product to have a positive z-component, \( \vec{B} \) should point in the negative y-direction which, according to the right-hand rule, will make \( \vec{A} \times \vec{B} \) point upwards along the z-axis.
Magnitude and Direction of Vectors
Vectors are characterized by both magnitude and direction. The magnitude of a vector represents its size or length and is often denoted as the absolute value of the vector in textbooks. For a vector \( \vec{A} \) described in the exercise, the magnitude is given as 5.00 m. The direction of a vector determines its orientation in space and can be described by the angle it makes with a reference axis, such as the x-axis in our example.

Determining the direction of a vector is crucial when computing the vector product since the resulting vector's orientation depends on the orientations of the two original vectors. For maximum or minimum magnitude of the cross product, it is essential to consider the vectors' directions such that they are perpendicular to each other, which, in our exercise, translates to specific angles from the reference axis for vector \( \vec{B} \) to achieve the desired positive or negative z-component.

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Most popular questions from this chapter

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