/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 A disoriented physics professor ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A disoriented physics professor drives \(3.25 \mathrm{~km}\) north, then \(2.20 \mathrm{~km}\) west, and then \(1.50 \mathrm{~km}\) south. Find the magnitude and direction of the resultant displacement, using the method of components. In a vector-addition diagram (roughly to scale), show that the resultant displacement found from your diagram is in qualitative agreement with the result you obtained by using the method of components.

Short Answer

Expert verified
The magnitude of the resultant displacement is \(2.79 \mathrm{~km}\) and the direction of the resultant displacement is \(51.34^\circ\) west of north.

Step by step solution

01

Identify the displacement vectors

Firstly, let's split the total displacement into its north-south and east-west components. The professor drives \(3.25 \mathrm{~km}\) north, \(2.20 \mathrm{~km}\) west, and then \(1.50 \mathrm{~km}\) south. We consider north and east as positive directions.
02

Calculate the north-south displacement

We calculate the north-south displacement by subtracting the southward displacement from the northward displacement. So, the net north-south displacement is: \(3.25 \mathrm{~km} - 1.5 \mathrm{~km} = 1.75 \mathrm{~km}\)
03

Determine the east-west displacement

As the professor is only traveling westward, the east-west displacement is \(2.20 \mathrm{~km}\) in the negative (westward) direction.
04

Compute the resultant displacement

To determine the magnitude of the resultant displacement, we apply Pythagoras theorem to the north-south and east-west displacements, treating them as perpendicular sides of a right-angled triangle. Hence, the magnitude of the resultant displacement is: \(\sqrt{(1.75 \mathrm{~km})^2 + (-2.20 \mathrm{~km})^2} = 2.79 \mathrm{~km}\)
05

Calculate the direction of the resultant displacement

Now, we calculate the direction of the resultant displacement by finding the arctangent of the ratio of the east-west displacement to the north-south displacement. It will give the angle west of north, which in this case is: \(\arctan(\frac{-2.20 \mathrm{~km}}{1.75 \mathrm{~km}}) = -51.34^\circ\). Since the result is negative, the resultant displacement is \(51.34^\circ\) west of north.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Components Method
In physics, the components method is essential for solving vector problems, especially those involving displacement. Displacement is a vector quantity that considers both magnitude and direction. The components method involves breaking down a vector into parts along the coordinate axes, usually the x-axis and y-axis. This makes it easier to manage and analyze complex vector quantities. To use this method:
  • Identify the directions of the components of the vector. In our example, north and east are positive directions.
  • Resolve each individual vector into its horizontal (east-west) and vertical (north-south) components.
  • Add up the similar components from different vectors. This means summing up all north-south components together and east-west components separately.
In our example, the north-south displacement was the difference between the northward and southward movements. The east-west displacement was straightforward as the motion was purely westward.
Pythagorean Theorem
The Pythagorean Theorem is a fundamental mathematical principle used to relate the lengths of the sides of a right triangle. This theorem is regularly used in physics to find the magnitude of a resultant vector when two vectors are perpendicular to each other.Let's consider the north-south and east-west components of the displacement as the two shorter sides of a right triangle:
  • North-south component: 1.75 km
  • East-west component: 2.20 km
According to the Pythagorean Theorem, the square of the hypotenuse (resultant vector or displacement in this case) is equal to the sum of the squares of these two sides:\[ c^2 = a^2 + b^2 \]By plugging in the values, we get:\[ c = \sqrt{(1.75)^2 + (2.20)^2} = 2.79 \text{ km} \]This result shows the magnitude of the resultant displacement as 2.79 km.
Arctangent Function
The arctangent function is a trigonometric function used to find an angle when given the opposite and adjacent sides of a right triangle. This is key when determining the direction of a resultant vector in vector displacement problems.The direction or angle of the resultant vector is found by:
  • Using the ratio of the east-west component to the north-south component.
  • Applying the arctangent function to calculate the angle.
In our example, for determining the direction of the resultant displacement, the angle is calculated as:\[ \theta = \arctan\left(\frac{-2.20}{1.75}\right) \]This yields an angle of approximately \(-51.34^\circ\). Since this angle is negative, it means the direction is west of north, clarifying that the resultant displacement points in this direction.
Resultant Vector
A resultant vector represents the combination of two or more vectors in magnitude and direction. It's critically important in understanding how different displacement vectors combine to show an overall change in position or motion.In calculating a resultant vector:
  • Firstly, sum up the components in each direction using the components method.
  • Utilize the Pythagorean Theorem to find the magnitude.
  • Use trigonometric functions, like the arctangent function, to identify its direction effectively.
In the given exercise, after resolving and summing the components of displacement, we used the Pythagorean Theorem to find that the magnitude was 2.79 km. The direction was determined to be \(51.34^\circ\) west of north. By understanding the resultant vector, one can easily visualize and determine how each individual displacement or vector contributes to the total movement.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

While following a treasure map, you start at an old oak tree. You first walk \(825 \mathrm{~m}\) directly south, then turn and walk \(1.25 \mathrm{~km}\) at \(30.0^{\circ}\) west of north, and finally walk \(1.00 \mathrm{~km}\) at \(32.0^{\circ}\) north of east, where you find the treasure: a biography of Isaac Newton! (a) To return to the old oak tree, in what direction should you head and how far will you walk? Use components to solve this problem. (b) To see whether your calculation in part (a) is reasonable, compare it with a graphical solution drawn roughly to scale.

Magnetic fields are produced by moving charges and exert forces on moving charges. When a particle with charge \(q\) is moving with velocity \(\overrightarrow{\boldsymbol{v}}\) in a magnetic field \(\overrightarrow{\boldsymbol{B}},\) the force \(\overrightarrow{\boldsymbol{F}}\) that the field exerts on the particle is given by \(\overrightarrow{\boldsymbol{F}}=q \overrightarrow{\boldsymbol{v}} \times \overrightarrow{\boldsymbol{B}}\). The SI units are as follows: For charge it is the coulomb (C), for magnetic field it is tesla (T), for force it is newton \((\mathrm{N}),\) and for velocity it is \(\mathrm{m} / \mathrm{s} .\) If \(q=-8.00 \times 10^{-6} \mathrm{C}, \overrightarrow{\boldsymbol{v}}\) is \(3.00 \times 10^{4} \mathrm{~m} / \mathrm{s}\) in the \(+x\) -direction, and \(\vec{B}\) is \(5.00 \mathrm{~T}\) in the \(-y\) -direction, what are the magnitude and direction of the force that the magnetic field exerts on the charged particle?

BIO Estimate the number of atoms in your body. (Hint: Based on what you know about biology and chemistry, what are the most common types of atom in your body? What is the mass of each type of atom? Appendix D gives the atomic masses of different elements, measured in atomic mass units; you can find the value of an atomic mass unit, or \(1 \mathrm{u},\) in Appendix E.)

A dog in an open field runs \(12.0 \mathrm{~m}\) east and then \(28.0 \mathrm{~m}\) in a direction \(50.0^{\circ}\) west of north. In what direction and how far must the dog then run to end up \(10.0 \mathrm{~m}\) south of her original starting point?

Let \(\theta\) be the angle that the vector \(\vec{A}\) makes with the \(+x\) - axis, measured counterclockwise from that axis. Find angle \(\theta\) for a vector that has these components: (a) \(A_{x}=2.00 \mathrm{~m}, A_{y}=-1.00 \mathrm{~m}\) (b) \(A_{x}=2.00 \mathrm{~m}, \quad A_{y}=1.00 \mathrm{~m}\) (c) \(A_{x}=-2.00 \mathrm{~m}, \quad A_{y}=1.00 \mathrm{~m}\) (d) \(A_{x}=-2.00 \mathrm{~m}, A_{y}=-1.00 \mathrm{~m}\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.