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BIO Horseshoe bats (genus Rhinolophus) emit sounds from their nostrils and then listen to the frequency of the sound reflected from their prey to determine the prey鈥檚 speed. (The 鈥渉orseshoe鈥 that gives the bat its name is a depression around the nostrils that acts like a focusing mirror, so that the bat emits sound in a narrow beam like a flashlight.) A Rhinolophus flying at speed vbat emits sound of frequency fbat; the sound it hears reflected from an insect flying toward it has a higher frequency frefl.(a) Show that the speed of the insect is

vinsect=vfreflv-vbat-fbatv+vbatfreflv-vbat+fbatv+vbatcv

where v is the speed of sound. (b) Iffbat = 80.7 kHz, frefl=83.5 kHz, andvbat = 3.9 m>s, calculate the speed of the insect.

Short Answer

Expert verified

A) We used the Doppler effect to find the frequency detected by the insect, then we used that frequency as the frequency of the sound reflected from the insect toward the bat, after that, we used some algebraic manipulation to get the result we wanted.

b) vinsect=1.97m/sis the speed of the insect.

Step by step solution

01

Formula of the frequency detected by the insect

The frequency emitted from the bat fbat, and the frequency detected by the bat after being reflected from the insect is frefl ,In the first case, the bat will be the source of sound that moves towards the listener "the insect"

The formula that describes the frequency detected by the insect, is f1=fsvvLvvs where, v, the speed of sound in the air, VL = vin sect the speed of the insect, vs = vbat, the speed of the source "the bat", the frequency detected by the insect, fs = fbat , the frequency emitted from the bat.

Therefore, equation can be written as role="math" localid="1668143929396" fL=fbatvvinsectvvbat(1)

02

Calculate the speed of the insect

Now, after the sound reflects from the insect, it will travel towards the bat and the frequency detected by the bat in so the equation (1) can be written as

frefl=fLv+vbatvvinsect(2)

Substitute fLin equation 2 from 1

frefl=fbatv+vinsectv-vbatv+vbatvvinsect

03

Equation to solve for 

freflfbat=v+vinsectvvinsectv+vbatvvbatfreflfbatvvbatv+vbat=v+vinsectvvinsect

Letfreflfbatvvbatv+vbat be x hence.

x=v+vinsectvvinsectxvvinsectx=v+vinsectvinsect+vinsectx=vxvvinsect(1+x)=v(x1)vinsect=v(x1)(1+x)

Now let鈥檚 replace x withfreflfbatvvbatv+vbat

vinsect=vfrefffbatvvbatv+vbat1freffbatvvbatv+vbat+1

Note that 1=fbatfbatv+vbatv+vbatHence,

vinsect=vfretfbatvvbatv+vbatfbatfbatv+vbatv+vbatfreffbatvvbatv+vbat+fbatfbatv+vbatv+vbat

vinsect=vfrefvvbatfbatv+vbatfreflvvbat+fbatv+vbat(1)

04

Substitute the values in equation 1

vinsect=34483.5103344-3.9-80.7103344+3.983.5103344-3.9+80.7103344+3.9=1.97m/s

Therefore, 1.97m/s is the speed of the insect.

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