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(a) If two sounds differ by 5.00 dB, find the ratio of the intensity of the louder sound to that of the softer one. (b) If one sound is 100 times as intense as another, by how much do they differ in sound intensity level (in decibels)? (c) If you increase the volume of your stereo so that the intensity doubles, by how much does the sound intensity level increase?

Short Answer

Expert verified

a) The ratio of the intensity is 3.16 b)Δβ=20db c)Δβ=3db

Step by step solution

01

STEP 1 The difference between the sound intensity levels for two different intensities

The formula is given byβ2-β1=10log(I2I1)where,l2is the new intensity and l1is the previous intensity

02

STEP 2 Find the ratio of these two intensities

Substitute the values in the equationβ2-β1=10log(I2I1)we get,

5db=10logl2l10.5=logl2l1100.5=l2l1l2l1=3.16

03

Step 3 Find the difference in sound intensity level between the two sounds

If the intensity of the first sound is l1, then the intensity of the second sound will be l2=100l1, to find the difference in sound intensity level between the two sounds ∆β, we need to substitute into (l) forl1 andl2

∆β=10log100l1l1=10log100=20db

Now the intensity of the second sound will be l2=2l1. Therefore, we get,

∆β=10log2l1l1=10log2=3db

Thus, the difference in sound intensity level between the two sounds is 3db

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