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Chapter 3: Q9E (page 610)

A large cylindrical tank contains 0.750m3of nitrogen gas at role="math" localid="1668235464848" 27掳Cand 7.50*103Pa(absolute pressure). The tank has a tight-fitting piston that allows the volume to be changed. What will be the pressure if the volume is decreased to 0.410m3and the temperature is increased to157掳C?

Short Answer

Expert verified

The pressure attained when the volume is decreased to0.410m3 and the temperature is increased to157掳C is 19.66*103Pa.

Step by step solution

01

Expression for pressure from the ideal gas equation

The ideal gas equation is PV=nRT, whereP is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, T is the temperature.

Write this as an equation for pressure P=nRTV, modified for initial and final cases as,

P1=nRT1V1

P2=nRT2V2., where n and R are constants. Combining both equations P2P1=T2V2T1V1, solve for the final pressureP2 as P2=P1T2V1T1V2.

02

Calculating   pressure

Substitute the values for P1=7.50*103Pa,T2=157鈭�C=157+273=430K,V1=0.750m3,V2=0.410m3,T1=27鈭�C=27+273=300KinP2=P1T2V1T1V2P2=7.50*103*430*0.750300*0.410P2=19.66*103Pa

Hence, the new pressure attained is 19.66*103Pa.

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Most popular questions from this chapter

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