91Ó°ÊÓ

The motor is running by the electric power. Suppose this power is ${\mathbf{P}}_{\mathbf{o}}$. Due to some resistance in the wires and the circuitry, a small portion of the energy is wasted into heat.The whole${\mathbf{P}}_{\mathbf{o}}$ power is not converted to mechanical energy. So, the achieved mechanical energy${\mathbf{P}}_{\mathbf{m}}$ is less thanrole="math" localid="1663830497933" ${\mathbf{P}}_{\mathbf{o}}$ .

${\mathrm{P}}_{\mathrm{m}}<{\mathrm{P}}_{\mathrm{o}}$

The generator converts mechanical energy to electrical energy. Due to the resistance in the circuitry,whole mechanical energy is Pm not converted into electrical energy. So, the achieved electrical energy role="math" localid="1663830396760" ${\mathbf{P}}_{\mathbf{el}}$is less than${\mathbf{P}}_{\mathbf{m}}$ .

${\mathrm{P}}_{\mathrm{el}}<{\mathrm{P}}_{\mathrm{m}}$

The achieved electrical energy is less than the achieved mechanical energy.

${\mathrm{P}}_{\mathrm{el}}<{\mathrm{P}}_{\mathrm{o}}$

The motor-generator combination itself is generating less power than it is consuming.

Therefore, the extra power needed for lighting the bulb cannot be achieved from the system.

Hence, the scheme is flawed.