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Chapter 3: Q45E (page 576)

How much heat is required to convert 18.0 g of ice at -10.0掳C to steam at 100.0掳C? Express your answer in joules, calories, and Btu.

Short Answer

Expert verified

The heat energy involved will be 36.4脳103J=8.7脳103cal=34.5Btu.

Step by step solution

01

Stages in the given process

The sample will go through four stages, the first stage includes the changing of the temperature of the ice but without any changes in the phase "it still ice", the second stage starts when the ice reaches its melting point and ends when all of the ice melts, the third stage includes rising of the temperature of the water but without any changes in the phase, the final stage includes the evaporation of the water.

02

Calculate the heat energy

The expression of heat energy involved will be

Qtotal=[0.012脳2100脳(0+10)]+(0.012脳33.4脳104)+[0.012脳4190脳(100-0)]+(0.012脳2256脳103)Qtotal=36.4脳103J

The conversions of units will be as follows

Qtotal=36.4脳103J脳1cal4.186J=8.7脳103calQtotal=36.4脳103J脳1Btu1055J=34.5Btu

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