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Chapter 3: Q34P (page 642)

You have 750 g of water at 10掳Cin a large insulated beaker. How much boiling water at 100掳Cmust you add to this beaker so that the final temperature of the mixture will be75掳C?

Short Answer

Expert verified

The boiling water is mboiling=1.95kg.

Step by step solution

01

Definition of Mixture

The term mixture may be defined as when two or more substances are combined but not combined chemically

02

Determine the amount of boiling water.

Consider the given data as below.

Initial mass of water, mbefore=750g=0.750kg

Initial temperature, T1=10掳C

Boiling temperature, T=100掳C

The final temperature, T2=75掳C

There is no heat change, heat before adding boiling water is equal to after adding boiling water.

Qbefore=Qaftermbefore脳C脳未罢1=mafter脳C脳未罢2mbefore脳C脳T2-T1=mafter脳C脳T-T2

Here, C is the heat capacity.

Substitute known values in the above equation.

0.750kg脳75-10掳C=mboiling100-75掳Cmboiling=1.95kg

Hence, the boiling water is mboiling=1.95kg.

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