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An interference pattern is produced by eight equally spaced narrow slits. The caption for Fig. 36.14 claims that minima occur for f =3π/4, π/4, 3π/2 and7π/4. Draw the phasor diagram for each of these four cases, and explain why each diagram proves that there is in fact a minimum. In each case, for which pairs of slits are there totally destructive interference?

Short Answer

Expert verified

As forϕ=3π4,π4,7π4 , there is destructive interference for each of the following pairs of slits: (1,5), (2,6),(3,7), and (4,8).

In case , each of the following pairs of slits cancels each other : (1,3 or 7),(2,4 or 8), (5,3 or 7), (6,4 or 8).

Step by step solution

01

Phasor and Destructive Interference

As shown in the figure the phasor diagrams, for an 8-slits interference pattern, for Ï•=3Ï€4,Ï€4,3Ï€4,and7Ï€4, and respectively. We see that the phasor diagram for Ï•=Ï€4is the same as for role="math" localid="1663903941522" Ï•=7Ï€4except that the direction of rotation is reversed.

The same goes for the phasor diagram for role="math" localid="1663903966954" ϕ=3π2andϕ=π2 .

In each of the four cases, the resultant phasor is zero, and the intensity is zero.

We observe the following. In case Ï•=3Ï€4,Ï€4,7Ï€4, there is destructive interference for each of the following pairs of slits: (1,5), (2,6),(3,7), and (4,8). In case Ï•=3Ï€2, each of the following pairs of slits cancels each other : (1,3 or 7),(2,4 or 8), (5,3 or 7), (6,4 or 8).

02

Figure

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