91影视

The refractive index of an optical material is expressed by n and represents the speed of light in the vacuum divided by the speed of light in the material. Snell's law is given by an equation in the form

$n_{air}\sin {胃}_a=n\sin {胃}_b$

Where $n_{air}$= 1 and n is the refractive index of the liquid. Now, we solve equation (1) for n and use the values for${胃}_a=60掳$ and${胃}_b$ , for each liquid as next

liquid A: (${胃}_b=36.4掳$)

$n=\frac{\sin {胃}_a}{\sin {胃}_b}=\frac{\sin 60掳}{\sin 36.4掳}=1.46$

we conclude that the liquid is Carbon tetrachloride

liquid B:${胃}_b=40.5掳$

$n=\frac{\sin {胃}_a}{\sin {胃}_b}=\frac{\sin 60掳}{\sin 40.5掳}=1.33$

we conclude that the liquid is Water

liquid C:${胃}_b=32.1掳$

$n=\frac{\sin {胃}_a}{\sin {胃}_b}=\frac{\sin 60掳}{\sin 32.1掳}=1.63$

, we conclude that the liquid is Carbon disulfide

liquid D:${胃}_b=35.2掳$

$n=\frac{\sin {胃}_a}{\sin {胃}_b}=\frac{\sin 60掳}{\sin 35.2掳}=1.50$

we conclude that the liquid is Benzene|

The dielectric is related to the refractive index by

$K=n^2$

So, for each liquid, we can get the dielectric by

Liquid A

$K_A=n_A^2={\left(1.46\right)}^2=2.13$

Liquid B

$K_B=n_B^2={\left(1.33\right)}^2=1.77$

Liquid C

$K_C={n_c}^2={\left(1.63\right)}^2=2.66$

Liquid D

$K_D=n_D^2={\left(1.50\right)}^2=2.25$

The frequency of the light doesn't change as the medium changes even the speed of the light change. So, the frequency for all liquids is the same

$f_A=f_B=f_C=f_D$

The frequency is related to the wavelength by

$f=\frac{c}{位}$

Now, plug the values for c and$位$ to get f

$f=\frac{c}{位}=\frac{3脳{10}^{8}m/s}{589脳{10}^{-9}m}=5.1脳{10}^{14}Hz$

Therefore, the frequency for each liquid is

$f_A=f_B=f_C=f_D=5.1脳{10}^{14}Hz$