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Chapter 5: Q13DQ (page 1211)

Explain, using phasor diagrams, why each statement is true. (a) A minimum occurs whenever 蠒 is an integral multiple of 2蟺/N, except when 蠒 is an integral multiple of 2蟺 (which gives a principal maximum). (b) There are (N-1) minima between each pair of principal maxima.

Short Answer

Expert verified

The 蠒 = 2n蟺 is a principal-maxima and there will be n-1 minima.

Step by step solution

01

Given Data

Diffraction is a process by which a beam of light spreads when passing through a narrow passage or across the edge of an obstacle accompanied by interference between the waveforms.

02

Reason for statements

The phasor for the above can be represented as:

It can be seen that for 蠒 = 2n蟺, multiplication of waves occurs with same phase which means there will be a single principal maxima.

Also, if n-slits are available then there will be n different phases, and excluding the one that is 2n蟺, it is evident to get n-1 minima.

Therefore, the 蠒 = 2n蟺 is a principal-maxima and there will be n-1 minima.

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