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In which of the following reactions or decays is strangeness conserved? In each case, explain your reasoning.

(a)K+→μ++νμ;

(b)n+K+→p+π0;

(c)K++K-→π0+π0;

(d)p+K-→Âì0+Ï€0.

Short Answer

Expert verified

The reactionsc,dare strangeness conserved

Step by step solution

01

Define Strangeness

The K mesons and the Âì0and Σhyperons are called the strange particles.

Strangeness is conserved in strong interactions, but it can change by 0 or 1.

02

Given information

Table representing strangeness quantum number of strange particles:

Strange particles

Strangeness quantum number


K+
+1
K-
-1
Âì0
-1
p
0
Ï€0
0
n
0
μ+
0
νμ
0


03

Check strangeness

a)

K+→μ++νμ

The strangeness of each side is:

For LHS =+1

And

for RHS=0

Since both sides are not equal, therefore, the reaction is not strangeness conserved.

b)

n+K+→p+π0

The strangeness of each side is:

For LHS =+1

And

for RHS =0

Since both sides are not equal, therefore, the reaction is not strangeness conserved.

c)

K++K-→π0+π0

The strangeness of each side is:

For LHS =0

And

for RHS =0

Since both sides are equal, therefore, the reaction is strangeness conserved.

d)

p+K-→Âì0+Ï€0

The strangeness of each side is:

For LHS =-1

And

for RHS =-1

Since both sides are equal, therefore, the reaction is strangeness conserved.

Hence, the reactions c,dare strangeness conserved.

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