91Ó°ÊÓ

The term momentum may be defined as the product of mass and its velocity.

The equations $\mathrm{L}=\sqrt{\mathrm{l}(\mathrm{l}+1)}\mathrm{h},{\mathrm{L}}_{\mathrm{z}}={\mathrm{m}}_{\mathrm{l}}\mathrm{h}$l=0, the value of${\mathrm{m}}_{\mathrm{l}}=0,Â\pm 1,Â\pm 2.....Â\pm \mathrm{l}$ we conclude that$\mathrm{L}>{\mathrm{L}}_{\mathrm{z}},$ except l=0 and in classical objects angular momentum is not an exception but any vector quantity has magnitude always larger or equal to one of its components. They are equal when the direction of angular momentum is totally in that given direction where all the other components are zero.

Hence, show that the orbital angular momentum of an electron in any given direction is always less than or equal to its total orbital angular momentum and they are equal when the direction of angular momentum is totally in that given direction where all the other components are zero and in classical objects angular momentum is not an exception but any vector quantity has magnitude always larger or equal to one of its components.