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In the process of internal conversion, a nucleus decays from an excited state to a ground state by giving the excitation energy directly to an atomic electron rather than emitting a gamma-ray photon. Why can this process also produce x-ray photons?

Short Answer

Expert verified

K-Because the emitted atomic electron collides with shell electron releases enough energy to escape from its level or escape from the atom. The release in energy causes a vacancy in the K-shell and an electron available in the outer falls into the vacancy causing a much lower level.

Step by step solution

01

Define the energy.

The energy Eof a photon is inversely proportional to the wavelength λof photon and directly proportional to the frequency fof wave.

E=hfE=hcλ

Where, the value of Planck’s constant h=6.626×10-34J·s.

02

Explanation.

K-When the emitted atomic electron collides with shell electron releases enough energy to escape from its level or escape from the atom. The release in energy causes a vacancy in the K-shell and an electron available in the outer falls into the vacancy causing a much lower level.

Therefore, emits the energy as a photon, and produce x-rays.

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