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A loaded grocery cart is rolling across a parking lot in a strong wind. You apply a constant force F=(30N)i^(40N)j^to the cart as it undergoes a displacement s=(9.0m)i^(3.0m)j^. How much work does the force you apply do on the grocery cart?

Short Answer

Expert verified

The total work applied by constant force to the grocery cart is -150 J.

Step by step solution

01

Identification of the given data

The given data is listed below as-

  • The magnitude of the force acting on the cart is, F=(30N)i^(40N)j^
  • The displacement is, s=(-9.0m)i^(3.0m)j^
02

Significance of the work done on a particle by a constant force

Work done on a particle by a constant forceFduring a linear displacementsis given by

W=Fs鈥︹赌︹赌︹赌.(1)

03

Determination of work applied by constant force to the grocery cart

The work done can be obtained using equation (1), such that

For, F=30Ni^-40Nj^ and s=-9.0mi^-3.0mj^

The total work done will be

W=Fxi^+Fyj^sxi^+syj^=Fxsx+Fysy=30N-9m+-40N-3m=-150NmW=-150J

The total work applied by constant force to the grocery cart is -150 J.

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