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Chapter 1: Q84 PP (page 99)

If a seed is launched at an angle of 0掳 with the maximum initial speed, how far from the plant will it land? Ignore air resistance, and assume that the ground is flat. (a) 20 cm; (b) 93 cm; (c) 2.2 m; (d) 4.6 m.

Short Answer

Expert verified

(b); The seed will land 0.92 mfrom the plant.

Step by step solution

01

Kinematic equations for projectile motion

For horizontal motion,

vx=uxx=xo+uxt

For vertical motion,

vy=uy+gty=yo+uyt+12gt2

02

Calculate the maximum horizontal distance covered by the seed.

Here the initial values of x and y value are zero. The maximum initial horizontal speed is 4.6 m/s. The initial speed in the vertical component is zero. The vertical height is 20 cm.Inserting this data into the vertical displacement equation

y=0+0+12gt2t=2yg=2(2.0m)9.8m/s2=0.20s

Insert this value in the horizontal displacement equation, and we get,

x=0+4.6m/s0.20s=0.92m

Hence, the seed will land 0.92 m from the plant.

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