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Chapter 1: Q62P (page 198)

A balky cow is leaving the barn as you try harder and harder to push her back in. In coordinates with the origin at the barn door, the cow walks from x=0 to x=6.9 m as you apply a force with x-component Fx=-[20鈥�N+(3鈥�N/m)x]. How much work does the force you apply do on the cow during this displacement?

Short Answer

Expert verified

The work done applied by the force on cow is 209.4 J

Step by step solution

01

Identification of given data

The given data can be listed below,

a) The x component of force is, Fx=-[20鈥�N+(3鈥�N/m)x]

b) The cow moves from x=0鈥�to鈥�x=6.9鈥�m

02

Concept/Significance of work done

If on the application of force on an object, it gets displaced from its initial position, the work is said to be done.

03

Determination of the work applied by force on cow.

The work done by force on cow is given by,

W=鈭�x1x2Fxdx

Substitute all the values in the above,

W=鈭�06.9m20N+3N/mxdx=-20Nx06.9m-3.0N/m126.9m2=-138N.m-71.4N=-209.4J

Thus, the work done applied by the force on cow is 209.4J

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