91影视

The given data can be listed below,

• The angle at which ropes are pulled is, $胃=72掳$.
• The resultant pull exerted is,$\mathrm{F}=372\mathrm{N}$.

Force is equal to the rate of momentum change with respect to time in any given situation, which facilitates the acceleration of an object

The magnitude of resultant of the components of two vectors in the y-direction is given by,

${\mathrm{C}}_{\mathrm{y}}={\mathrm{A}}_{\mathrm{y}}+{\mathrm{B}}_{\mathrm{y}}$

Here, $A_y$is the magnitude of y-component of force $\stackrel{鈬赌}{A}$, $B_y$is the magnitude of y-component of force $\stackrel{鈬赌}{B}$
and $C_y$is the magnitude of resultant of forces,$\stackrel{鈬赌}{A}$and $\stackrel{鈬赌}{B}$.

Assuming y-axis lies along the north, the three vectors, their magnitudes and their direction areshown in the diagram given below,

The magnitude of the two vectors is equal. and they make equal angle $胃$with the y-axis.

Therefore,

$$\begin{gathered} {\mathrm{A}}_{\mathrm{y}}={\mathrm{B}}_{\mathrm{y}} \\ =\mathrm{Acos}\left(\mathrm{胃}\right) \\ =\mathrm{Acos}{36}^{掳} \end{gathered}$$

Substitute values in the equation of resultant force, the value of A is given by,

$$\begin{gathered} \mathrm{A}\mathrm{肠辞蝉胃}+\mathrm{B}\mathrm{肠辞蝉胃}={\mathrm{C}}_{\mathrm{y}} \\ \mathrm{A}\cos 36掳+\mathrm{A}\cos 36掳=372 \\ 2\mathrm{A}\cos 36掳=372 \\ \mathrm{A}=230\mathrm{N} \end{gathered}$$

Thus, the pull exerted by each rope is $230\mathrm{N}$.