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A water hose is used to fill a large cylindrical storage tank of diameter D and height 2D. The hose shoots the water at 45°above the horizontal from the same level as the base of the tank and is a distance 6D away (Fig. P3.56). For what range of launch speeds(v0) will the water enter the tank? Ignore air resistance, and express your answer in terms of D and g.

Short Answer

Expert verified

The range of speed will be3gDand3.13gD.

Step by step solution

01

Introduction

The velocity contains two components, one is horizontal component and another one is vertical.

According to the newton’s laws of motion,

s=ut+12at2

Where, s, u, t, a, are displacement, initial velocity, time and acceleration.

02

Given

Angle =45°

03

Explanation

For the vertical motion, gravity is negative

sv=uvtv-12gtv2

For the horizontal motion, gravity is zero

sH=uHtH

When the water goes in the with the minimum velocity,

sv=2D,sH=6D

When the water goes in the with the maximum velocity,

sv=2D,sH=7D

In both the cases,

sin45°=cos45°=1/2

To reach minimum distance,

2D=u2t-12gt2and6D=u2t2D=u262Du12g62Du2u=3gD

To reach maximum distance,

2D=u2t-12gt2and7D=u2t2D=u272Du-12g72Duu=3.13gD

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