91影视

Cable length isl = 5

Theupper end of the cable is fastened to the arm at a point d = 3.00m from the central shaft

The force applied to an item in curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.

A fictitious force that moves in a circle and is directed away from the centre of the circle is called centrifugal force.

$F_c=\frac{m{v}^2}{r}ormr{蝇}^2$

Where, m is mass of body, v is velocity of body, r is radius of circular path and the$蝇$ is angular speed

Equating the vertical forces

$T\sin 60掳=mg$ 鈥�(颈)

Equating the horizontal forces

$$\begin{gathered} T\cos 60掳=F_c \\ =mr{蝇}^2 \end{gathered}$$ 鈥�(颈颈)

Dividing of equation (i) by the equation of (ii)

$$\begin{gathered} \tan 60掳=\frac{g}{r{蝇}^2} \\ 蝇=\sqrt{\frac{g}{r\tan 60掳}} \end{gathered}$$ 鈥�(颈颈颈)

Where is radius of curvature and it is given as

$$\begin{gathered} r=d+l\sin 30掳 \\ =3m+5m脳\sin 30掳 \\ =5.5m \end{gathered}$$

Substitute all values in the equation (iii)

$$\begin{gathered} 蝇=\sqrt{\frac{9.8m/s^2}{5m脳\tan 60掳}} \\ =1.063rad/s \end{gathered}$$
Time of one revolution is given by

$t=\frac{2\mathrm{蟺}}{蝇}$

Substitute the$蝇$ value to get time

$$\begin{gathered} t=\frac{2\mathrm{蟺}}{1.063rad/s} \\ =5.91s \end{gathered}$$

Hence the time of one revolution of the swing is5.91 s

Equation (iii) is given as

$\tan 60掳=\frac{g}{r{蝇}^2}$

From the above equation here we can see that the term of mass is not present so that we can say that the angle does not depend on the weight of the passenger for a given rate of revolution