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A golf course sprinkler system discharges water from a horizontal pipe at the rate of 7200 cm3/s. At one point in the pipe, where the radius is 4.00 cm, the water鈥檚 absolute pressure is2.40105Pa . At a second point in the pipe, the water passes through a constriction where the radius is 2.00 cm. What is the water鈥檚 absolute pressure as it flows through this constriction?

Short Answer

Expert verified

The absolute pressure of water is2.24105Pa .

Step by step solution

01

Given data

  • The water is flowing at a rate ofdVdt=7200cm3/s.
  • The absolute pressure of water isP1=2.40105Pa.
  • The radius at one point isr1=4cm.
  • The radius at second point isr2=2cm.
02

Concept of the Bernoulli’s equation

In this problem, Bernoulli鈥檚 equation will be applied to evaluate the absolute pressure. In this case, the pipe is horizontal, so the vertical components will be equal to zero.

03

Determination of the speed of the water at one point

The relation of speed can be written as:

V1=dVdtAV1=dVdtr12

Substitute7200cm3/s fordVdt and4cmfor r1in the above relation.

v1=7200cm3/s1m3/s106cm3/s4cm1m100cm2v1=1.43m/s

04

Determination of the speed of the water at a second point

The relation of speed can be written as:

A1V1=A2v2V2=r12v1r22

Substitute 1.43 m/s forv1 , 4 cm forr1 and2cm forr2 in the above relation.

v2=4cm1m100cm2(1.43m/s)2cm1m100cm2v2=5.72m/s

05

Determination of the water’s absolute pressure

The relation of absolute pressure of water can be written as:

P1+12v12=P2+12v22P2=P1+12v12v22

Here,is the density of water andP2is the required pressure.

Substitute 2.40105Pafor P1, 1000kg/m3for , 1.43 m/s for v1and5.72m/s for in the above relation.

P2=2.40105Pa+121000kg/m3(1.43m/s)2(5.72m/s)2P2=2.24105Pa

Thus, the absolute pressure is2.24105Pa.

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