91影视

The given data is listed below as:

• The weight of yours is, w = 683 N
• The first reading of the scale is,$n_1=725N$
• The second reading of the scale is,${\mathrm{n}}_2=595\mathrm{N}$

Newton鈥檚 second law states that the force applied to an object is directly proportional to the mass and the acceleration of the object. The weight of that object is also proportional to the mass of that object.

The equation of the acceleration of the elevator is expressed as:

$$\begin{gathered} n_1-w=ma \\ a=\frac{n_1-w}{m} \end{gathered}$$

Here, a is the acceleration of the elevator in the first case,$n_1$is the first reading of the first scale, w is your weig ht and m is your mass.

Substitute$\frac{w}{g}$ for m in the above equation.

$$\begin{gathered} n_1-w=ma \\ a=\frac{n_1-w}{{\displaystyle \frac{w}{g}}} \end{gathered}$$ 鈥�(颈)

Here,g is the acceleration due to gravity with value$9.8m/s^2$.

Substitute all the values in the above equation.

$$\begin{gathered} \mathrm{a}=\frac{725\mathrm{N}-683\mathrm{N}}{{\displaystyle \frac{683\mathrm{N}}{9.8\mathrm{m}/{\mathrm{s}}^2}}} \\ =\frac{42\mathrm{N}}{683\mathrm{N}}\left(9.8\mathrm{m}/{\mathrm{s}}^2\right) \\ =0.06\left(9.8\mathrm{m}/{\mathrm{s}}^2\right) \\ =0.602\mathrm{m}/{\mathrm{s}}^2 \end{gathered}$$

As the acceleration is positive, hence it is directed upwards.

Thus, the magnitude of the elevator鈥檚 acceleration is$0.602\mathrm{m}/{\mathrm{s}}^2$and it is in the upwards direction.

Substitute all the values in equation (i).

$$\begin{gathered} \mathrm{a}=\frac{595\mathrm{N}-683\mathrm{N}}{{\displaystyle \frac{683\mathrm{N}}{9.8\mathrm{m}/{\mathrm{s}}^2}}} \\ =\frac{-88\mathrm{N}}{683\mathrm{N}}\left(9.8\mathrm{m}/{\mathrm{s}}^2\right) \\ =-0.12\left(9.8\mathrm{m}/{\mathrm{s}}^2\right) \\ =-1.26\mathrm{m}/{\mathrm{s}}^2 \end{gathered}$$

As the acceleration is positive, hence it is directed downwards.

Thus, the magnitude of the elevator鈥檚 acceleration is $-1.26\mathrm{m}/{\mathrm{s}}^2$ and it is in the downwards direction.