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The given data is listed below as:

• The mass of the automobile is,$m=850\mathrm{kg}$

• The speed of the automobile is,$\mathrm{v}=45.0\mathrm{km}/\mathrm{h}脳\left(\frac{1000\mathrm{m}}{1\mathrm{km}}\right)脳\left(\frac{1\mathrm{h}}{3600\mathrm{s}}\right)=12.5\mathrm{m}/\mathrm{s}$

• The dime鈥檚 diameter is equal to the distance traveled by automobile$1.8鈥�"\mathrm{cm}"脳\left(\frac{{10}^{-2}鈥�\mathrm{m}}{1\mathrm{cm}}\right)=1.8脳{10}^{-2}\mathrm{m}$.

This law states that the force applied by an object is directly proportional to the product of the acceleration and the mass of the object. The acceleration occurs as a force acts on a particular mass.

The equation of the acceleration of the automobile is expressed as:

$\begin{array}{l}{\mathrm{v}}^2={\mathrm{u}}^2+2\mathrm{as}\\ \mathrm{a}=\frac{{\mathrm{v}}^2-{\mathrm{u}}^2}{2\mathrm{s}}\end{array}$

鈥�(颈)

Here, $\mathrm{V}$is the final speed, $u$is the initial speed, $a$is the acceleration of the automobile, and $s$is the distance traveled by automobile.

Use equation (i) for writing the equation of the net force.

$\begin{array}{l}\mathrm{F}=\mathrm{m}\\ ={\mathrm{m}}^2-{\mathrm{u}}^2\\ 2\mathrm{s}\end{array}$

Here, $m$is the mass of the automobile.

Substitute all the values in the above equation.

$$\begin{gathered} F=\left(850\mathrm{kg}\right)\frac{{\left(12.5\mathrm{m}/\mathrm{s}\right)}^2}{2\left(1.8脳{10}^{-2}\right)} \\ =\left(850\mathrm{kg}\right)\frac{\left(156.25{\mathrm{m}}^2/{\mathrm{s}}^2\right)}{} \\ =\left(850\mathrm{kg}\right)\left(4340.27\mathrm{m}/{\mathrm{s}}^2\right) \\ =3.6脳{10}^6\mathrm{kg}.\mathrm{m}/{\mathrm{s}}^2 \end{gathered}$$

$$\begin{gathered} F=\left(850\mathrm{kg}\right)\frac{{\left(12.5\mathrm{m}/\mathrm{s}\right)}^2-{\left(0\right)}^2}{2\left(1.8脳{10}^{-2}\mathrm{m}\right)} \\ =\left(850\mathrm{kg}\right)\frac{\left(156.25{\mathrm{m}}^2/{\mathrm{s}}^2\right)}{\left(0.036\mathrm{m}\right)} \\ =\left(850\mathrm{kg}\right)\left(4340.27\mathrm{m}/{\mathrm{s}}^2\right) \\ =3.6脳{10}^6\mathrm{kg}.\mathrm{m}/{\mathrm{s}}^2 \end{gathered}$$

Hence, further as:

$$\begin{gathered} F=3.6脳{10}^6\mathrm{kg}.\mathrm{m}/{\mathrm{s}}^2脳\left(\frac{1\mathrm{N}}{1\mathrm{kg}.\mathrm{m}/{\mathrm{s}}^2}\right) \\ =3.6脳{10}^6\mathrm{N} \end{gathered}$$

$\mathrm{Thus},\mathrm{the}\mathrm{net}\mathrm{force}\mathrm{required}\mathrm{to}\mathrm{stop}\mathrm{the}\mathrm{automobile}\mathrm{is}3.6脳{10}^6\mathrm{N}.$