91影视

The vector's various coordinates are presented here. We know that in coordinates, the $x$ component of a vector comes first, followed by the $y$ component. To calculate the angle of the vector with respect to the $x$-axis, just multiply the $y$ component by the $x$component and then take the inverse of that result.

This will tell you the vector's angle with the$x$-axis.

It can be represented as

The vector $\mathrm{A}$is $(-8.60\mathrm{cm},5.20\mathrm{cm})$

The magnitude of the vector can be calculated by the sum of the square of the magnitude of the individual coordinates

Hence the magnitude of vector$A$is $10.04\mathrm{cm}$

The counterclockwise angle taken from the positive $\mathrm{x}$-axis is given by equation (1), such that,

Hence vector $A$ makes the angle of $149掳$ and magnitude is $10.04\mathrm{cm}$.

The vector $A$is $(-9.70\mathrm{m},-2.45\mathrm{m})$

The magnitude of the vector can be calculated by the sum of the square of the magnitude of the individual coordinates

Hence the magnitude of vector A is $10.04\mathrm{cm}$

The counterclockwise angle taken from the positive $\mathrm{x}$-axis is given by equation (1), such that,

Hence vector A makes the angle of $194.2掳$ and magnitude is $10.0\mathrm{m}$.

The vector $\mathrm{A}$ is $(-9.70\mathrm{m},-2.45\mathrm{m})$

The magnitude of the vector can be calculated by the sum of the square of the magnitude of the individual coordinates

Hence the magnitude of vector A is $8.21\mathrm{km}$

The counterclockwise angle taken from the positive x-axis is given by equation (l), such that,

Hence vector A makes the angle of$109.2掳$ and magnitude is $8.21\mathrm{km}$.

Therefore for case (a) the angle of the vector is $149掳$ and magnitude is $10.04\mathrm{cm}$, for case (b) the angle of the vector is $14.2掳$and magnitude is $10.0\mathrm{m}$, and in case (c) the angle of the vector is $109.2掳$ and magnitude is $8.21\mathrm{km}$.