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Chapter 1: Q33E (page 60)

A small block has constant acceleration as it slides down a frictionless incline. The block is released from rest at the top of the incline, and its speed after it has travelled 6.80 m to the bottom of the incline is 3.80 m/s. What is the speed of the block when it is 3.40 m from the top of the incline?

Short Answer

Expert verified

Speed when travelling is top of the incline= 2.687 m/s.

Step by step solution

01

Identification of the given data

  • Speed when travelling is bottom of the incline=3.80 m/s.
  • Distance travelled = 6.80 m.
02

calculation for the speed

Total speed is calculated by using ,

v2=u2+(2脳a脳s)

Where, v= final velocity, u=initial velocity, a=acceleration due to gravity, and s=distance travelled

Substituting the values ,

3.82=0+(2脳a脳6.80)a=0.941

Now using the value of a for calculation of speed when distance travelled is3.40 m,

Substituting the given values,

v2=0+(2脳0.941脳3.40)v2=6.3988v=6.3988v=2.687m/s

Thus, the final speed of the block isv=2.687m/s

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