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An engine delivers 175hpto an aircraft propeller at 2400rev/min. (a) How much torques does the aircraft engine provide? (b)How much work does the engine do in one revolution of the propeller?

Short Answer

Expert verified

(a) The torque provided by the aircraft engine is =519Nm.

(b)The work done by the engine in one revolution of the propeller isW=3261J.

Step by step solution

01

To state given data

Power P=175hp.

Angular speed =2400revmin.

02

Recall the concepts

The power is calculated by the following formula,

P=蟿蝇 鈥︹ (1)

Here, is the torque and is the angular speed.

Therefore, the torque is given by,

=P 鈥︹. (2)

Now, the power in hp is converted into watts by using conversion:

1hp=746W.

Therefore, the conversion is done as:

175hp746W1hp=130500W.

Also, the angular speed is also converted into rad/s as follows:

1rev=260rads.

Therefore,

2400revmin30radsminrev=80rads.

03

(a) Find the torque

Let us calculate the torque.

Then from 2and solve:

=13050080=519Nm

Hence, the torque provided by the aircraft engine is =519Nm.

04

(b) Find the work done by the engine

The work done by the engine in one revolution of the propeller is calculated by using the formula given by,

W=,

Here, 1 revolution is equivalent to 2.

Solve as:

W=5192W=3261J

Hence, the work done by the engine in one revolution of the propeller isW=3261J.

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