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You pull horizontally on block B in Fig. E4.26, causing both blocks to move together as a unit. For this moving system, make a carefully labeled free-body diagram of block A if (a) the table is frictionless and (b) there is friction between block B and the table and the pull is equal in magnitude to the friction force on block B due to the table.

Short Answer

Expert verified

(a) The free-body diagram of block A if the table is frictionless is,

(b) In the free-body diagram of block A if there is friction between block B and the table and the pull is equal in magnitude to the friction force on block B due to the table is,

Step by step solution

01

Significance of friction force

Whenever a specific surface is referred to as frictionless, it means the surface would not offer any friction force. The relation between the friction force and friction coefficient of the surface material is a direct linear one.

02

(a) Drawing the free body diagram of block A if the table is frictionless

The free-body diagram of block A if the table is frictionless is given below.


Here, WAis the weight of block A, NAis the normal reaction force on block A and Ffis the friction force that acts on block A due to the friction between block A and block B.

Since the table is frictionless, the friction force between the table and block A does not exist and results as the value of friction force acts on block A would be equal to the value of pull force.

03

(b) Drawing the free body diagram of block A if there is friction between block B and the table and the pull is equal in magnitude to the friction force on block B due to the table

In the free-body diagram of block A if there is friction between block B and the table and the pull is equal in magnitude to the friction force on block B due to the table is given below.

Here, WAis the weight of the block A and NAis the normal reaction force on block A.

Since the pull is equal in magnitude to the friction force on block B due to the table, block B would be stationary, resulting in block A being also stationary. Therefore, the friction force between block A and block B would not exist.

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