/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q26E Two circular rods, one steel and... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Q26E (page 359)

Two circular rods, one steel and the other copper, are joined end to end. Each rod is 0.750 m long and 1.50 cm in diameter. The combination is subjected to a tensile force with magnitude 4000 N . For each rod, what are (a) the strain and (b) the elongation?

Short Answer

Expert verified

(a) Steel :1.1脳10-4

Copper :1.1脳10-4

(b) Steel :8.3脳10-5m

Copper:1.6脳10-4m

Step by step solution

01

Given information

Tensile force: F = 4000 N,

l0=0.75m

Area=(d24)=((1.50脳10-2m)24)=1.77脳10-4m2

02

Concept/Formula used

Y=l0F鈭�l

Where, Y is Young鈥檚 modulus, l0 is length of muscle, F is muscle force, A is cross-sectional area and 鈭�l is elongation.

03

(a) Strain Calculation

The strain is :鈭�ll0=FYA

For steel: Y=2.0脳1011Pa

鈭�ll0=4000N(2.0脳1011Pa)(1.77脳10-4m2)=1.1脳10-4

For copper :Y=1.1脳1011Pa

鈭�ll0=4000N(1.1脳1011Pa)(1.77脳10-4m2)=2.1脳10-4

04

Elongation Calculation

For steel:

(1.1脳10-4)(0.75)=8.3脳10-5m

For Copper:

(2.1脳10-4)(0.75)=1.6脳10-4m

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Water flows steadily from an open tank as in Fig. P12.81. The elevation of point 1 is 10.0 m, and the elevation of points 2 and 3 is 2.00 m. The cross-sectional area at point 2 is 0.0480 m2; at point 3 it is 0.0160 m2. The area of the tank is very large compared with the cross-sectional area of the pipe. Assuming that Bernoulli鈥檚 equation applies, compute (a) the discharge rate in cubic meters per second and (b) the gauge pressure at point 2.

The acceleration of a particle is given by ax(t)=鈭�2.00鈥�m/s2+(3.00鈥�m/s3)t. (a) Find the initial velocityv0xsuch that the particle will have the same x-coordinate att=4.00鈥�sas it had att=0. (b) What will be the velocity att=4.00鈥�s?

An antelope moving with constant acceleration covers the distance between two points 70.0apart in6.00s. Its speed as it passes the second point is15.0m/s. What are (a) its speed at the first point and (b) its acceleration?

Question: A car鈥檚 velocity as a function of time is given byvxt=伪+尾t2, where伪=3.00m/sand 尾=0.100m/s3.(a) Calculate the average acceleration for the time interval t=0tot=5.00s. (b) Calculate the instantaneous acceleration forrole="math" t=0tot=5.00s.

(c) Draw vx-tandax-tgraphs for the car鈥檚 motion betweent=0tot=5.00s.

Three horizontal ropes pull on a large stone stuck in the ground, producing the vector forces A鈬赌, B鈬赌, andC鈬赌 shown in Fig. P1.60. Find the magnitude and direction of a fourth force on the stone that will make the vector sum of the four forces zero.
See all solutions

Recommended explanations on Physics Textbooks

Electricity and Magnetism

Read Explanation

Famous Physicists

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Fundamentals of Physics

Read Explanation

Linear Momentum

Read Explanation

Geometrical and Physical Optics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.