91Ó°ÊÓ

The given data can be listed below,

The acceleration in a uniform circular motion that is pointed in that direction is referred to as centripetal or radial acceleration.

The linear velocity of the blade is given by,

$v=\mathrm{Ó\neg }r$

Here, $\mathrm{Ó\neg }$is the angular velocity of the blade, and r is the radial distance.

Substitute all the values in the above,

$\begin{array}{rcl}v& =& 550rev/s\left(\frac{2\mathrm{π}}{60}\frac{rad/s}{rev/min}\right)×3.4m\\ & =& 57.6rev/s\left(3.4m\right)\\ & =& 195.8m/s\end{array}$

Thus, the linear velocity of the blade is 195.8 m/s.

The radial acceleration of the object is given by,

$a_r=\frac{v^2}{R}$

Here, v is the velocity of the blade and R is the radius of rotor.

Substitute all the values in the above.

$\begin{array}{rcl}{a}_r& =& \frac{{\left(195.8m/s\right)}^2}{3.4m}\\ & =& 11275.8m/s^2\left(\frac{g}{9.8m/s^2}\right)\\ & =& 1.15×{10}^{3}g\end{array}$

Thus, the radial acceleration of the blade tip is $11275.8m/s^{2}or1.15×{10}^{3}g$.