91Ó°ÊÓ

A sort of energy that an item or particle possesses as a result of its mobility is known as kinetic energy. When an item undergoes work—the transfer of energy—by being subjected to a net force, it accelerates and consequently obtains kinetic energy.

Initially, both the objects were at rest, so the total moment of the system consists of two masses and a string was zero. Since there is no external force acting on the system so after the string is decompressed the total moment should be zero.

Since spring has negligible mass, its moment is zero, so two objectsmust have an equal magnitude of momentum in the opposite direction.

Therefore, it is true that two objects receive an equal magnitude of momentum.

We know the kinetic energy of an object is

$k=\frac{1}{2}m{v}_2$….(¾±)

The mom of an object

$p=mv$…â¶Ä¦(¾±¾±)

From equations (i) and (ii)

$$\begin{gathered} k=\frac{1}{2}m{v}_2 \\ k=\frac{1}{2}\frac{m^2{v}^2}{m}=\frac{1}{2}\frac{P^2}{m} \end{gathered}$$

Suppose the kinetic energy of an object with the massofM is$K_1$

$K_1=\frac{1}{2}\frac{P^2}{M}$

Suppose the kinetic energy of an object with a mass of 5M is$K_2$

$K_2=\frac{1}{2}\frac{P}{5M}$

Therefore,

$K_2=\frac{K_1}{5}$

This implies lighter body will receive more kinetic energy

Hence the statement is false.

We know the kinetic energy of an object is

$k=\frac{1}{2}m{v}^2$….(¾±)

The mom of an object

$p=mv$…â¶Ä¦(¾±¾±)

From equations (i) and (ii)

$$\begin{gathered} k=\frac{1}{2}m{v}^2 \\ K=\frac{1}{2}\frac{m^{2}v{2}^2}{m}=\frac{1}{2}\frac{P^2}{m} \end{gathered}$$

Suppose the kinetic energy of an object with the mass of M is$K_1$

$K_1=\frac{1}{2}\frac{P^2}{M}$

Suppose the kinetic energy of an object with a mass of 5M is$K_2$

$K_2=\frac{1}{2}\frac{P}{5M}$

Therefore

$K_2=\frac{K_1}{5M}$

This implies lighter body will receive more kinetic energy

Hence the statement is false

We know the kinetic energy of an object is

$k=\frac{1}{2}m{v}^2$….(¾±)

The mom of an object

$p=mv$…â¶Ä¦(¾±¾±)

From equations (i) and (ii)

$$\begin{gathered} K=\frac{1}{2}m{v}^2 \\ K=\frac{1}{2}\frac{m^2{v}^2}{m}=\frac{1}{2}\frac{P^2}{m} \end{gathered}$$

Suppose the kinetic energy of an object with the mass of M is$K_1$

role="math" localid="1663953503963" $K_1=\frac{1}{2}\frac{P^2}{M}$

Suppose the kinetic energy of an object with a mass of 5M is$K_2$

$K_2=\frac{1}{2}\frac{P}{M}$

Therefore

$K_2=\frac{K_1}{5}$

This implies lighter body will receive more kinetic energy

Hence the statement is true.