91Ó°ÊÓ

The amplitude of motion can be defined as the maximum distance that an object travels before coming back to its original position.

The period can be defined as the time taken required to complete one cycle or oscillation.

Frequency is defined as the number of oscillations done by an object per second.

It is given that the spring travels from $-0.120m$to $+0.120m$. Thus, its amplitude is the maximum distance its travels from the equilibrium position.

Therefore, the amplitude is $0.120m$.

Consider the given data as below.

Time,$t=0.800s$

In this question, the given time is the time required by object to complete half cycle i.e. it moves either left or right from the origin in that given time. Therefore, the time period in this case will be,

$$\begin{gathered} t=\frac{T}{2} \\ T=2t \end{gathered}$$

Here, T is the time period.

Substitute value of in above expression to get time period.

role="math" localid="1663932862451" $$\begin{gathered} T=2\left(0.800S\right) \\ =1.6S \end{gathered}$$

Therefore, the time period is$1.6S$ .

The relation between frequency and time period is given by,

$f=\frac{1}{T}$

Substitute value of in above expression to get frequency

$$\begin{gathered} f=\frac{1}{1.6s} \\ =0.625Hz \end{gathered}$$

Therefore, the frequency is 0.625 Hz.