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The graph in Fig. E2.31 shows the velocity of a motorcycle police officer plotted as a function of time. (a) Find the instantaneous acceleration at \(t = 3\,s,\,\,t = 7\,s{\rm{ and }}t = 11\,s\).

Short Answer

Expert verified

Hence, the required accelerations are

\({a_3} = 0{\rm{ m/}}{{\rm{s}}^2},\,\,\,{a_7} = 6.25{\rm{ m/}}{{\rm{s}}^2},\,\,{\rm{and }}\,{a_{11}} = - 11.25{\rm{ m/}}{{\rm{s}}^2}\).

Step by step solution

01

Velocity and Acceleration

The measurement of change of displacement with respect to time is known as velocity, whereas that of velocity with respect to time is known as acceleration.

02

Examine the given graph(a)

The graph for velocity of a motorcycle as a function of time is:

Now, at\(t = 3\,s\), the velocity is constant.

Therefore, acceleration at \(t = 3\,s\) will be zero.

And, from\(t = 3\,s{\rm{ to }}t = 7\,s\), there is change in the velocity.

Therefore, acceleration here will be:

\({a_7} = \frac{{\Delta v}}{{\Delta t}} = \frac{{45 - 20}}{{7 - 3}} = \frac{{25}}{4} = 6.25{\rm{ m/}}{{\rm{s}}^2}\)

03

Find acceleration

Similarly,from\(t = 7\,s{\rm{ to }}t = 11\,s\), there is change in the velocity.

Therefore, acceleration here will be:

\({a_{11}} = \frac{{\Delta v}}{{\Delta t}} = \frac{{0 - 45}}{{11 - 7}} = \frac{{ - 45}}{4} = - 11.25{\rm{ m/}}{{\rm{s}}^2}\)

Hence, the required acceleration are

\({a_3} = 0{\rm{ m/}}{{\rm{s}}^2},\,\,\,{a_7} = 6.25{\rm{ m/}}{{\rm{s}}^2},\,\,{\rm{and }}\,{a_{11}} = - 11.25{\rm{ m/}}{{\rm{s}}^2}\).

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