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The acceleration caused by gravity on a free-falling object is referred to as acceleration owing to gravity. The acceleration owing to gravity is the acceleration of a body caused only by gravity's attraction.

When a stone is launched into the air at an angle over horizontal and encounters minimal air resistance, it moves with uniform retardation. The body comes to a halt for a brief while before moving with uniform acceleration in the opposite direction of its original motion.

There will be two parts to the velocity. One component will be horizontal, while the other will be vertical. Throughout the trajectory, the horizontal component of the velocity will remain constant which is given by

$u_x=u_{0x}t$

Here,$u_x$is the horizontal component of velocity,$v_{0x}$isthe horizontal component of the beginning velocity, and tthe trip time.

The vertical component of the velocity will initially drop due to gravity acting downwards, and then it will begin to increase until it reaches its minimal value. the governing equation is given by,

$u_y=u_{0y}t+\frac{1}{2}g{t}^2$

Here,$u_y$ is the vertical component of velocity,$u_{0y}$ is the vertical component of the beginning velocity, and tis the trip duration.

The stone's velocity at any location is given by,

$u=\sqrt{u_x^2+u_y^2}$

The overall velocity is constant because the horizontal component of velocity is constant throughout the motion. It will solely be determined by the velocity's vertical component. As a result, the velocity will first drop until it hits a minimal value, after which it will begin to increase.

The proper graph for the stone's speed as a function of time is given by,

Thus, option d is correct for speed of stone as a function of time.