/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q13E A turntable rotates with a const... [FREE SOLUTION] | 91影视

91影视

A turntable rotates with a constant2.25rad/s2angular acceleration. After 4.00 s it has rotated through an angle of 30.0 rad. What was the angular velocity of the wheel at the beginning of the 4.00-s interval?

Short Answer

Expert verified

The required angular velocity is 3 rad/s.

Step by step solution

01

Identification of given data

The angular accelerationis z=2.25rad/s2.

The angular displacement is-0=30rad .

The time is t=4s.

02

Concept/Significance of rotation of body with constant angular acceleration

Angular position at time t of a rigid body with constant angular acceleration is given by,

-0=0zt+12zt2......(1)

Here, is Angular position of body at time 0.

03

Determine the angular velocity of the wheel at the beginning of the 4.00-s interval

Substitute -0=30rad, role="math" localid="1664351624177" t=4s, andz=2.25rad/s2 in equation (1).

30rad=0z4s+122.25rad/s24s20z4s=30rad-18rad0z=12rad4s=3rad/s

Therefore, the required angular velocity is 3 rad/s .

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Hot Jupiters. In 2004 astronomers reported the discovery of a large Jupiter-sized planet orbiting very close to the star HD179949 (hence the term 鈥渉ot Jupiter鈥). The orbit was just19 the distance of Mercury from our sun, and it takes the planet only3.09days to make one orbit (assumed to be circular). (a) What is the mass of the star? Express your answer in kilograms and as a multiple of our sun鈥檚 mass. (b) How fast (in km>s) is this planet moving?

In Wagner鈥檚 opera Das Rheingold,the goddess Freia is ransomed for a pile of gold just tall enough and wide enough to hide her from sight. Estimate the monetary value of this pile. The density of gold is 19.3 g/cm3, and take its value to be about $10 per gram.

At what distance above the surface of the earth is the acceleration due to the earth鈥檚 gravity 0.980 m/s2 if the acceleration due to gravity at the surface has magnitude 9.8 m/s2?

A physics professor leaves her house and walks along the sidewalk toward campus. After 5 min, it starts to rain, and she returns home. Her distance from her house as a function of time is shown in Fig. E2.10 At which of the labeled points is her velocity (a) zero? (b) constant and positive? (c) constant and negative? (d) increasing in magnitude? (e) decreasing in magnitude?

An astronaut has left the International Space Station to test a new space scooter.

Her partner measures the following velocity changes, each taking place in a 10-sinterval.

What are the magnitude, the algebraic sign, and the direction of the average acceleration in each interval?

Assume that the positive direction is to the right.

(a) At the beginning of the interval, the astronaut is moving toward the right along the x-axis at 15.0m/s, and at the end of the interval she is moving toward the right at5.0m/s .

(b) At the beginning she is moving toward the left atrole="math" localid="1655276110547" 5.0m/s , and at the end she is moving toward the left at 15.0m/s.

(c) At the beginning she is moving toward the right at , and at the end she is moving toward the left atrole="math" localid="1655276636193" 15.0m/s .

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.