/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q13DQ If a projectile is fired straigh... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 1: Q13DQ (page 424)

If a projectile is fired straight up from the earth鈥檚 surface, what would happen if the total mechanical energy (kinetic plus potential) is (a) less than zero, and (b) greater than zero? In each case, ignore air resistance and the gravitational effects of the sun, the moon, and the other planets.

Short Answer

Expert verified

(a)The projectile will fall back to the earth.

(b) The projectile will get out from the atmosphere of the earth.

Step by step solution

01

Significance of the mechanical energy

Mechanical energy is the energy possessed by a particular object due to its position or its motion.

The concept of mechanical energy gives the correct answer.

02

(a) Determination of the effect if the mechanical energy is less than zero

If the kinetic plus the potential energy of an object is lesser than zero, then the object may not be able to achieve the escape velocity and it will also fall back to the surface of the earth.

Thus, the projectile will fall back to the earth.

03

(b) Determination of the effect if the mechanical energy is greater than zero

If the kinetic plus the potential energy of an object is greater than zero, then the object will achieve a large amount of speed to escape the gravitational clutch of the earth because the object goes towards the infinity.

Thus, the projectile will get out from the atmosphere of the earth.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Planet Vulcan.Suppose that a planet were discovered between the sun and Mercury, with a circular orbit of radius equal to 2/3 of the average orbit radius of Mercury. What would be the orbital period of such a planet? (Such a planet was once postulated, in part to explain the precession of Mercury鈥檚 orbit. It was even given the name Vulcan, although we now have no evidence that it actually exists. Mercury鈥檚 precession has been explained by general relativity.)

The most efficient way to send a spacecraft from the earth to

another planet is to use a Hohmann transfer orbit(Fig. P13.79). If the orbits of

the departure and destination planets are circular, the Hohmann transfer orbit

is an elliptical orbit whose perihelion and aphelion are tangent to the orbits of

the two planets. The rockets are fired briefly at the departure planet to put the spacecraft into the transfer orbit; the spacecraft then coasts until it reaches

the destination planet. The rockets are then fired again to put the spacecraft

into the same orbit about the sun as the destination planet. (a) For a flight from

earth to Mars, in what direction must the rockets be fired at the earth and at

Mars: in the direction of motion or opposite the direction of motion? What

about for a flight from Mars to the earth? (b) How long does a one-way trip

from the earth to Mars take, between the firings of the rockets? (c) To reach

Mars from the earth, the launch must be timed so that Mars will be at the right

spot when the spacecraft reaches Mars鈥檚 orbit around the sun. At launch, what

must the angle between a sun鈥揗ars line and a sun鈥揺arth line be? Use

Appendix F.

For a spherical planet with mass M, volume V, and radius R,derive an expression for the acceleration due to gravity at the planet鈥檚 surface, g, in terms of the average density of the planet, 蚁=M/V, and the planet鈥檚 diameter, D=2R. The table gives the values of Dand gfor the eight major planets:

(a) Treat the planets as spheres. Your equation for as a function of and shows that if the average density of the planets is constant, a graph of versus will be well represented by a straight line. Graph as a function of for the eight major planets. What does the graph tell you about the variation in average density? (b) Calculate the average density for each major planet. List the planets in order of decreasing density, and give the calculated average density of each. (c) The earth is not a uniform sphere and has greater density near its center. It is reasonable to assume this might be true for the other planets. Discuss the effect this nonuniformity has on your analysis. (d) If Saturn had the same average density as the earth, what would be the value of at Saturn鈥檚 surface?

A circular racetrack has a radius of 500 m. What is the displacement of a bicyclist when she travels around the track from the north side to the south side? When she makes one complete circle around the track? Explain.

On a training flight, a student pilot flies from Lincoln, Nebraska, to Clarinda, Iowa, next to St. Joseph, Missouri, and then to Manhattan, Kansas

(Fig. P1.66). The directions are shown relative to north: 0掳is north, 90掳is east, 180掳is south, and 270掳is west. Use the method of components to find (a) the distance she has to fly from Manhattan to get back to Lincoln, and (b) the direction (relative to north) she must fly to get there. Illustrate your solutions with a vector diagram.
See all solutions

Recommended explanations on Physics Textbooks

Electrostatics

Read Explanation

Waves Physics

Read Explanation

Scientific Method Physics

Read Explanation

Dynamics

Read Explanation

Magnetism and Electromagnetic Induction

Read Explanation

Atoms and Radioactivity

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.