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The rotating blade of a blender turns with constant angular acceleration1.5rad/s2 . (a) How much time does it take to reach an angular velocity of 36.0 rad/s, starting from rest? (b) Through how many revolutions does the blade turn in this time interval?

Short Answer

Expert verified

(a) The required time is24s .

(b) The number of revolutions are68.8rev .

Step by step solution

01

Identification of given data

The angular acceleration isαz=1.50rad/s2 .

The initial angular speed isÓ¬0z=rad/s .

The final angular speed isÓ¬z=36rad/s .

02

Concept/Significance of rotation of body with constant angular acceleration

The straight-line motion is particularly simple when the acceleration is constant. This is also true of rotational motion about a fixed axis.

Angular velocity at time t of a rigid body with constant angular acceleration is given by,

Ӭz=Ӭ0z+αzt.......(1)

Here, is the angular acceleration, Ó¬0zis the angular velocity of body at time 0, t is the time.

Angular position at time t of a rigid body with constant angular acceleration is given by,

θ=θ0+Ӭ0zt+12αzt2.........(2)

Here, is Angular position of body at time 0.

03

Determine the time taken by the blade to reach an angular velocity of 36.0 rad/s, starting from rest(a)

Substitute ,Ӭ0z=0rad./s,Ӭz=36rad/s,andαz=1.5rad/s2in equation (1).

36rev/s=0rev/s+1.5rad/s2tt=36rev/s1.5rad/s2=24s

Therefore, the required time is 24s .

04

Determine the number of revolution of the blades(b)

Substituteθ0=0,Ӭz=0rad/s,t=24s,andαz=1.5rad/s2 in equation (2).

θ=0+024s+121.5rad/s224s2=432rad=432rad1ev2πrad=68.8rev

Therefore, the number of revolutions are68.8rev .

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