/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q11DQ A planet is moving at constant s... [FREE SOLUTION] | 91影视

91影视

A planet is moving at constant speed in a circular orbit around a star. In one complete orbit, what is the net amount of work done on the planet by the star鈥檚 gravitational force: positive, negative, or zero? What if the planet鈥檚 orbit is an ellipse, so that the speed is not constant? Explain your answers.

Short Answer

Expert verified

The net work done on the planet by the star鈥檚 gravitational force in the circular orbit is zero.

the net work done on the planet by the star鈥檚 gravitational force in the elliptical orbit is zero.

Step by step solution

01

Significance of the gravitational force

The attractive force between two objects by virtue of their mass is called gravitational force.

The concept of the gravitational force gives the net amount of work done.

02

Determination of the net amount of work done if the orbit is circular

As the gravitational force is regarded as a conservative force, then the work done is the difference in the potential energy of the two points.

Let the planet has moved in a conservative field of force from the point A to the point B in the path C, then the equation of the work done is expressed as:

W=CF.dr=UB-UA

Here, W is the work done, F is the force exerted, dr is the distance travelled, U(B) is the potential energy at point B and U(A) is the potential energy at point A.

As the orbit has been completed and as it is circular, then the planet will start and end both at the point A. Hence, the work done will be-

W=U(A)-U(A)=0

Thus, the net work done on the planet by the star鈥檚 gravitational force in the circular orbit is .

03

Determination of the work done if the orbit is ellipse

In case of elliptical orbit, as the planet is moving closer to the star, it increases its speed and hence the work done is positive. In the same way, as the planet moves away from the star, it reduces its speed and hence does equal amount of negative work. So net work done in one complete revolution is zero.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A car and a truck start from rest at the same instant, with the car initially at some distance behind the truck. The truck has a constant acceleration of20m/s2, and the car has an acceleration of3.40m/s2. The car overtakes the truck after the truck has moved60.0m. (a) How much time does it take the car to overtake the truck? (b) How far was the car behind the truck initially? (c) What is the speed of each when they are abreast? (d) On a single graph, sketch the position of each vehicle as a function of time. Takex=0at the initial location of the truck.

A useful and easy-to-remember approximate value for the number of seconds in a year is饾洃脳107. Determine the percent error in this approximate value. (There are 365.24 days in one year.)

How many gallons of gasoline are used in the United States in one day? Assume that there are two cars for every three people, that each car is driven an average of 10,000 miles per year, and that the average car gets 20 miles per gallon.

In 2005 astronomers announced the discovery of large black hole in the galaxy Markarian 766 having clumps of matter orbiting around once every27hours and moving at30,000km/s . (a) How far these clumps from the center of the black hole? (b) What is the mass of this black hole, assuming circular orbits? Express your answer in kilogram and as a multiple of sun鈥檚 mass. (c) What is the radius of event horizon?

An 8.00kg point mass and a12.00kg point mass are held50.0cm apart. A particle of mass mis released from a point between the two masses20.0cm from the8.00kg group along the line connecting the two fixed masses. Find the magnitude and direction of the acceleration of the particle.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.