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You throw a rock downward into water with a speed of 3 mg/k, where k is the coefficient in Eq. (5.5). Assume that the relationship between fluid resistance and speed is as given in Eq. (5.5), and calculate the speed of the rock as a function of time.

Short Answer

Expert verified

The speed of the rock as a function of time is v=2mgk12+e-ktm.

Step by step solution

01

Identify the given data

  • The speed of the rock is v=mgk.
02

Find the speed of the rock as a function of time

Using Newton’s second law for the falling ball as:

mdvdt=kvt-mgmkdvdt=kvt-mgk

Here, m is mass of an object, k is constant,vtis terminal velocity, andvis the velocity of the object.

It is given that mgk=v.

mkdvdt=vt-v-mkdvdt=v-vtdvv-vt=-kmdt

Integrate both sides of the above equation by taking the lower limit as 3vt.

∫3vtvdvv-vt=-ktmlnv-vt3vtv=-ktmlnv-vt2vt=-ktmlnv2vt-12=-ktm

Simplify further as:

v=2vt12+e-ktm=2mgk12+e-ktm

Therefore, the speed of the rock as a function of time is v=2mgk12+e-ktm.

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