91影视

Here different coordinates of the vector are given. We are knowing that in coordinates x component of the vector will be first and then the y component. Now to find the angle of the vector with respect to the x-axis we just need to take the ratio of the y component to that of the x component and then take the tan inverse of that value.

This will give you the angle of the vector with the x-axis.

It can be represented as

$\mathbf{胃}\mathbf{=}{\mathbf{tan}}^{\mathbf{-}\mathbf{1}}\left(\frac{y}{x}\right)$鈥︹赌︹赌︹赌︹赌︹赌︹赌�(1)

Substitute the given data in equation (1), and we get,

$$\begin{gathered} 胃={\tan }^{-1}\left(\frac{A_y}{A_x}\right) \\ ={\tan }^{-1}\left(\frac{-1.00m}{2.00m}\right) \\ ={\tan }^{-1}\left(\frac{-1}{2}\right) \\ =-26.6掳 \\ =360掳-26.6掳 \\ =333.4掳 \end{gathered}$$

Substitute the given data in equation (1), and we get,

$$\begin{gathered} 胃={\tan }^{-1}\left(\frac{A_y}{A_x}\right) \\ ={\tan }^{-1}\left(\frac{1.00m}{2.00m}\right) \\ ={\tan }^{-1}\left(\frac{1}{2}\right) \\ =26.6掳 \end{gathered}$$

Substitute the given data in equation (1), and we get,

$$\begin{gathered} 胃={\tan }^{-1}\left(\frac{A_y}{A_x}\right) \\ ={\tan }^{-1}\left(\frac{-1.00m}{2.00m}\right) \\ ={\tan }^{-1}\left(\frac{-1}{2}\right) \\ =-26.6掳 \\ =360掳-26.6掳 \\ =333.4掳 \end{gathered}$$

Substitute the given data in equation (1), and we get,

$$\begin{gathered} 胃={\tan }^{-1}\left(\frac{A_y}{A_x}\right) \\ ={\tan }^{-1}\left(\frac{-1.00m}{-2.00m}\right) \\ ={\tan }^{-1}\left(\frac{1}{2}\right) \\ =26.6掳 \end{gathered}$$

Therefore the angle made by the vectors is (a)$333.4掳$, (b)$26.6掳$, (c)$333.4掳$, and

(d)$26.6掳$.