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Chapter 4: Q9E (page 809)

A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and the outer is positively charged; the magnitude of the charge on each is 10.0 pC. The inner cylinder has a radius of 0.50 mm, the outer one has a radius of 5.00 mm, and the length of each cylinder is 18.0 cm. (a) What is the capacitance? (b) What applied potential difference is necessary to produce these charges on the cylinders?

Short Answer

Expert verified

The Capacitance is 4.35脳10-12F.

The electric voltage required to keep this charge is given by 2.3V.

Step by step solution

01

Step 1:

Given Q=10脳10-12C,ra=0.5mm,ra=0.5脳10-3m,L=180cm

The capacitance of the coaxial cylinder according is given

Substitute in equation(1)


The electric voltage required to keep this charge is given by

02

Step 2:

The Capacitance is4.35脳10-12F.

The electric voltage required to keep this charge is given by 2.3V.

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