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Chapter 4: Q72P (page 846)

Consider the circuit shown in Fig. P25.72. The battery has emf 72.0 Vand negligible internal resistance. R2=2.00惟,C1=3.00渭F,andC2=6.00渭F. After the capacitors have attained their final charges, the charge on C1is Q1=18.0渭C. What is (a) the final charge onC2; (b) the resistanceR1?

Short Answer

Expert verified
  1. The final charge on C2is36渭C
  2. The resistance R1is 22惟

Step by step solution

01

Determine the final charge on C2

The two capacitors are in parallel, so they have the same voltage.

V=Q1C1V=18渭F3渭FV=6V

Therefore, the charge Q2on C2is 6 V

02

Determine the resistance R1

We know that, R2is in parallel with C1and C2, thus the voltage is same between the two terminals of R1. So, the current that flows through the circuit is

I=VR2I=62=3A

The internal resistance of the battery is zero, so

蔚=IR1+R2R1=鈭�I-R2

Substitute the values

R1=鈭�I-R2R1=723-2R1=22惟

Therefore, the resistance R1is22惟

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