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An insulating spherical shell with inner radius 25.0 cm and outer radius 60.0 cm carries a charge of +150.0μ°äuniformly distributed over its outer surface. Point a is at the center of the shell, point b is on the inner surface, and point c is on the outer surface. (a) What will a voltmeter read if it is connected between the following points: (i) a and b; (ii) b and c; (iii) c and infinity; (iv) a and c? (b) Which is at higher potential: (i) a or b; (ii) b or c; (iii) a or c? (c) Which, if any, of the answers would change sign if the charge were -150μC?

Short Answer

Expert verified
  1. Potential difference between points is
  1. 0V
  2. 0V
  3. 2.25×106V
  4. 0V
  5. Potential is the same in all the cases.
  6. Sign is negative.

Step by step solution

01

Step 1:

(a) As the enclosed chargeqenforr<ri is zero and the potential is constant and equivalent to the potential at the outer surface.

And as the enclosed charge is zero forri<r<r0and the potential is constant and equal to the outer surface potential.

Therefore for r>r0the enclosed charge is the net charge,

So, the potential is

Vr=KQr

And potential at the surface

Vr0=KQr0

02

Step 2:

So, the potential difference between the points is:

(i) For a and b

Vab=Va-Vb=Vr0-Vr0=0V

(ii) For b and c

Vbc=Vb-Vc=Vr0-Vr0=0V

(iii) For c and infinity

Va∞=Va-V∞=kQr0-0=9×109×150×10-60.6=2.25×106V



(iv) For a and c

Vac=Va-Vc=Vr0-Vr0=0V

03

Step 3:

(b) Thus, the Potential will remain the same for (a, b, c) and will be equal to the surface potential.

04

Step 4:

(c) If a charge is changed the electric potential will equal a, b, and c with a negative value.

Thus, the potential at a, b and c will be

-2.25×106V

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