91影视

The term magnetic field may be defined as the area around the magnet behave like a magnet.

On the loop torque is calculate by

$\stackrel{鈫�}{蟿}=\stackrel{鈫�}{渭}脳\stackrel{鈫�}{B}$

And the angle between magnetic field and moment is

then

$\begin{array}{r}蟿=\mathrm{IABsin}鈦�\left({60}^{鈭�}\right)\\ 蟿=\left(15.0\mathrm{A}\right)\left(0.060\mathrm{m}\right)\left(0.080\mathrm{m}\right)\left(048\mathrm{T}\right)\sin 鈦�\left({60}^{鈭�}\right)\\ 蟿=0.030\mathrm{N}.\mathrm{m}\end{array}$

The direction of torque in the negative axis according to right hand thumb rule.

$\stackrel{鈫�}{蟿}=\left(0.030\mathrm{N}.\mathrm{m}\right)\hat{j}$

Hence, the magnitude and direction of the torque is $\stackrel{鈫�}{蟿}=\left(0.030\mathrm{N}.\mathrm{m}\right)\hat{j}$.

And in the direction of axis the angle between magnetic field and moment is $30掳$

$\begin{array}{r}蟿=\text{IABsin}\left({30}^{鈭�}\right)\\ 蟿=\left(15\mathrm{A}\right)\left(0.060\mathrm{m}\right)\left(0.080\mathrm{m}\right)\left(0.48\mathrm{T}\right)\sin 鈦�\left({30}^{鈭�}\right)\\ 蟿=0.017\mathrm{N}.\mathrm{m}\end{array}$

The direction of torque in the negative axis according to right hand thumb rule.

${\stackrel{鈫�}{蟿}}^{\mathrm{鈥�}}=0.017\text{N.m}$

Hence, the magnitude and direction of the torque in - z direction is $蟿=鈭�\left(0.017\text{N.m}\right)\widehat{j}$.

And in last case the force parallel to rotational axis but lever arm is only half as before.ie force is doubled but area is halved. Torque for both cases are identical would be required if the loop were pivoted about an axis through its center, parallel to the y - axis.

Hence, torque for both cases are identical would be required if the loop were pivoted about an axis through its center, parallel to the y - axis.