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In the circuit shown in Fig. P30.57, the switch S has been open for a long time and is suddenly closed. Neither the battery nor the inductors have any appreciable resistance. What do the ammeter and the voltmeter read (a) just after S is closed; (b) after S has been closed a very long time; (c) 0.115 ms after S is closed?

Short Answer

Expert verified

A) Current is i=emfRfor RC circuit and i=0for RL circuit b) Current is zero for RC circuit and iR=emfRfor RL circuit.

Step by step solution

01

Concept when S is closed

Just after the switch is closed in the R 鈥 C circuit, the current flow through the resistor R and the initial current is i=emfRWhile just after the switch is closed in the R 鈥 L circuit, the current wouldn't flow through the circuit and the initial current is zero.i=0

02

Concept when after S has been closed a very long time

After a long time, for R 鈥 C circuit, the uncharged capacitor will be charged with the same potential of the battery and in this case, the current will be zeroi=0 For R 鈥 L circuit, the change on current in the inductor will be zero, while through the resistance it will be constantiR=emfR

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Most popular questions from this chapter

In the circuit shown in Fig. E26.47 each capacitor initially has a charge of magnitude 3.50 nC on its plates. After the switch S is closed, what will be the current in the circuit at the instant that the capacitors have lost 80.0% of their initial stored energy?

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