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A Radio Tuning Circuit: The minimum capacitance of a variable capacitor in a radio is 4.18 pF. (a) What is the inductance of a coil connected to this capacitor if the oscillation frequency of the L-C circuit is 1600 * 103 Hz, corresponding to one end of the AM radio broadcast band, when the capacitor is set to its minimum capacitance? (b) The frequency at the other end of the broadcast band is 540 * 103 Hz. What is the maximum capacitance of the capacitor if the oscillation frequency is adjustable over the range of the broadcast band?

Short Answer

Expert verified
  1. the inductance of the coil is 2.37 milli-henry.
  2. the maximum capacitance of the capacitor is 36.7 pF.

Step by step solution

01

Basic Definition

An inductor is a passive two-terminal device that stores energy in a magnetic field when current passes through it. An inductor stores the energy in form of magnetic field.

A capacitor is a device consisting of two conductors in close proximity that are used to store electrical energy. A capacitor stores energy in form of electric field.

An LC-circuit can store energy while oscillating at its natural resonant frequency. For such circuits, the energy in the circuit shifts between electric and magnetic fields. The angular frequency of this oscillation is given by

=2饾憮=1LC

02

Inductance of coil

We are given,

Minimum capacitance of variable capacitor, C = 4.18 pF

Frequency of oscillation, f = 1600 x 103 Hz

Self-Inductance of a toroidal solenoid is given by

=2饾憮=1LCL=142饾憮2CL=1421600*100024.18*10-12L=2.37饾懃10-3HL=2.37mH

Therefore, the inductance of the coil is 2.37 milli-henry.

03

Maximum capacitance of capacitor

Maximum capacitance at the given minimum frequency is

=2饾憮=1LCC=142饾憮2LC=1425.40*105Hz22.37*10-3HC=3.67饾懃10-11HC=3.67pF

Therefore, the maximum capacitance of the capacitor is 36.7 pF.

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