91Ó°ÊÓ

The power transported per unit area is known as the intensity ( I ).

The formula used to calculate the intensity( I ) is:

$I=\frac{P}{A}$

Where,$A$ is area measured in the direction perpendicular to the energy and$P$ is the power in watts.

The relation between the frequency of wave $\left(f\right)$, wavelength$\left(\mathrm{λ}\right)$ and speed of light$\left(c\right)$ is:

$c=f\mathrm{λ}$

And also, $I=\frac{1}{2}{\mathrm{Î\mu }}_{0}c{E}_{max}^2$ . Where, I is the intensity in $\mathrm{W}/{\mathrm{m}}^2$and is the speed of light that is equal to $3.0×{10}^8\mathrm{m}/\mathrm{s}$and ${\mathrm{Î\mu }}_0=8.85×{10}^{-12}{\mathrm{C}}^2/\mathrm{N}·{\mathrm{m}}^2$.

The relation between the maximum electric field and maximum magnetic field is:

$B_{max}=\frac{E_{max}}{c}$

Given that,$\mathrm{λ}=35.4×{10}^{-2}\mathrm{m}$

The frequency of wave is:

$$\begin{gathered} f=\frac{c}{\mathrm{λ}} \\ =\frac{3×{10}^8}{35.4×{10}^{-2}} \\ =8.47×{10}^8\mathrm{Hz} \end{gathered}$$

Hence, the frequency of wave is $8.47×{10}^8\mathrm{Hz}$.

Given that,$E_{max}=5.4×{10}^{-2}V/m$

The amplitude of magnetic field is:

$$\begin{gathered} B_{max}=\frac{E_{max}}{c} \\ =\frac{5.4×{10}^{-2}}{3×{10}^8} \\ =1.8×{10}^{-10}\mathrm{T} \end{gathered}$$

Hence, the amplitude of magnetic-field is $1.8×{10}^{-10}\mathrm{T}$.

The intensity of wave:

$$\begin{gathered} I=\frac{1}{2}{\mathrm{Î\mu }}_{0}c{E}_{max}^2 \\ =\frac{1}{2}×\left(8.854×{10}^{-12}\right)\left(3×{10}^8\right)\left(5.4×{10}^{-2}\right) \\ =3.87×{10}^{-6}\mathrm{W}/{\mathrm{m}}^2 \end{gathered}$$

Hence, intensity of wave is $3.87×{10}^{-6}\mathrm{W}/{\mathrm{m}}^2$.