/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q21E A small, circular ring is inside... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A small, circular ring is inside a larger loop that is connected to a battery and a switch (Fig. E29.21). Use Lenz’s law to find the direction of the current induced in the small ring (a) just after switch S is closed; (b) after S has been closed a long time; (c) just after S has been reopened after it was closed for a long time.

Short Answer

Expert verified
  1. The direction of the induced current in the smaller loop is clockwise.
  2. There is no induced current in the smaller loop.
  3. The direction of the induced current in the smaller loop is counterclockwise.

Step by step solution

01

About Lenz law.

Lenz's law: Lenz's law states that an induced current or emf always tends to oppose or cancel out the change that caused it.

Right-hand rule for a magnetic field produced by a current in a loop: When the fingers of your right hand curl in the direction of the current, your right thumb points in the direction of the magnetic field lines.

02

Conditions on Lenz law

When the switch S is closed, the current flows in the circuit in the direction of the +

terminal to the - terminal of the battery.

Using the right-hand rule on the larger loop, we curl the fingers of the right hand, and

we find that the right thumb is pointing outward (.)(out of the screen)

Thus, whenever the switch S is closed, the magnetic field produced by the current in

the larger loop at the smaller loop is directed outward (.).

03

When the switch is closed.

(a) When switch S is closed after having been opened for a while, the current in the

the loop is increased from zero to a finite value, and so the magnetic field.

So, the magnetic field at the smaller loop is increasing.

Applying Lenz's law, this change in the magnetic field at the smaller loop induces a

current in the smaller loop to oppose this change.

So, the magnetic field produced by the induced current is to decrease the magnetic

field directed outward (.).

Thus, the magnetic field produced by the smaller loop is directed inward (x)(into the

screen)

Using the right-hand rule, point your right thumb in the direction of the magnetic field

inward (x), so your right fingers now curl in the direction of the induced current

Therefore, the direction of the induced current in the smaller loop is clockwise.

04

The switch is closed for a long time.

(b)When switch S is closed for a long time, the current in the loop does not change, and so does the magnetic field.

So, the magnetic field at the smaller loop is constant.

Since

Φ=constant,dΦ/dt=0

Applying Faraday’s law, the induced current in the smaller loop is:

ε=dΦdt=0

Therefore, there is no induced current in the smaller loop.

05

Switch is opened after closing a long time a long time.

(c) When switch S is reopened after having been closed for a long time, the current in the loop decreases to zero, and so does the magnetic field.

So, the magnetic field at the smaller loop is decreasing

Applying Lenz's law, this change in the magnetic field at the smaller loop induces a

current in the smaller loop to oppose this change.

So, the magnetic field produced by the induced current is to increase the magnetic

field directed outward(.).

Thus, the magnetic field produced by the smaller loop is directed outward (•)( out of

the screen).

Using the right-hand rule, point your right thumb in the direction of the magnetic field

outward (.), so your right fingers now curl in the direction of the induced current.

Therefore, the direction of the induced current in the smaller loop is counterclockwise

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

You connect a battery, resistor, and capacitor as in Fig. 26.20a, where R = 12.0 Ω and C = 5.00 x 10-6 F. The switch S is closed at t = 0. When the current in the circuit has a magnitude of 3.00 A, the charge on the capacitor is 40.0 x 10-6 C. (a) What is the emf of the battery? (b) At what time t after the switch is closed is the charge on the capacitor equal to 40.0 x 10-6 C? (c) When the current has magnitude 3.00 A, at what rate is energy being (i) stored in the capacitor, (ii) supplied by the battery

If you peel two strips of transparent tape off the same roll and immediately let them hang near each other, they will repel each other. If you then stick the sticky side of one to the shiny side of the other and rip them apart, they will attract each other. Give a plausible explanation, involving transfer of electrons between the strips of tape, for this sequence of events.

Two parallel-plate capacitors, identical except that one has twice the plate separation of the other, are charged by the Same voltage source. Which capacitor has a stronger electric field Between the plates? Which capacitor has a greater charge? Which has greater energy density? Explain your reasoning.

If you carry out the integral of the electric field S for a closedpath like that shown in Fig. Q23.9, the integral will alwaysbe equal to zero, independent of the shape of the path and independent of where charges may be located relative to the path. Explain why

The heating element of an electric dryer is rated at 4.1 kW when connected to a 240-V line. (a) What is the current in the heating element? Is 12-gauge wire large enough to supply this current? (b) What is the resistance of the dryer’s heating element at its operating temperature? (c) At 11 cents per kWh, how much does it cost per hour to operate the dryer?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.