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Chapter 4: Q18E (page 1073)

A sinusoidal electromagnetic wave from a radio station passes perpendicularly through an open window that has area0.500m2. At the window, the electric field of the wave has rms value 0.0400 V/m . How much energy does this wave carry through the window during a 30.0s - commercial?

Short Answer

Expert verified

63.72脳10-6Jenergy the wave carries through the window during 30.0 s commercial.

Step by step solution

01

Define the intensity ( l ) and the formulas.

The power transported per unit area is known as the intensity ( l ) .

The formula used to calculate the intensity ( l ) is:

l=PA

Where, a is area measured in the direction perpendicular to the energy and P is the power in watts.

And also,l=12蔚0cEmax2 . Where, l is the intensity inW/m2 and is the speed of light that is equal to 3.0脳108m/s and also

Em:s=Emax2蔚0=8.85脳10鈭�12C2/N鈰�m2

The energy of flowF=lAt .

02

Given values

Given that,

A=0.500m2Emms=0.0400V/mt=30.0s

03

Calculation

The energy of flow is

F=lAt

Substitute in above equation

F=蔚0cEms2At

Now, again substitute the values

role="math" localid="1668164488988" F=8.85脳10鈭�123脳108(0.0400)(0.5)(30)=63.72脳10鈭�6J

Hence, the energy of flow is equal to63.72脳10-6J .

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